Magnetic flux in a straight wire to a cylinder

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SUMMARY

The discussion focuses on calculating the total magnetic flux through a cylinder caused by a long, straight wire carrying a current of 3.00 A. The magnetic field (B) is determined using the formula B = (μ₀ * I) / (2 * π * r), where μ₀ is the magnetic constant. The area (A) of the cylinder is calculated, and the magnetic flux is derived using the equation flux = B * A * cos(theta). The angle theta is zero since the magnetic field is parallel to the area vector of the cylinder's end face.

PREREQUISITES
  • Understanding of magnetic fields and their calculations
  • Familiarity with the formula for magnetic flux
  • Knowledge of the magnetic constant (μ₀)
  • Basic geometry of cylinders
NEXT STEPS
  • Study the derivation of the magnetic field around a straight wire
  • Learn about the applications of magnetic flux in electromagnetic theory
  • Explore the relationship between current, magnetic field, and force on charged particles
  • Investigate the implications of magnetic flux in real-world applications like inductors
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in the practical applications of magnetic fields in cylindrical geometries.

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Homework Statement



A long, straight wire carrying a current of 3.00 A is placed along the axis of a cylinder of radius 0.500 m and a length of 5.00 m. Determine the total magnetic flux through the cylinder.

Homework Equations



flux=BAcostheta

The Attempt at a Solution


i found the area of the cylinder first and i don't have any idea where to go from there. I am not really finding any helpful equations...
 
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Obviously, you have to calculate the magnetic field due to the current.
 
borgwal said:
Obviously, you have to calculate the magnetic field due to the current.

would i use B= (Moconstant)I/2pir??
 
Yep.
 

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