Magnetic flux - magnitude of the change

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SUMMARY

The discussion revolves around calculating the magnitude of the change in magnetic flux for a 200-loop coil with a cross-sectional area of 8.5 cm², subjected to a magnetic field that decreases from 0.060 T to 0.020 T over 12 milliseconds. The correct formula for magnetic flux is Φ = B * A * N, where B is the magnetic field, A is the area, and N is the number of loops. The initial calculation of 6.8 * 10^-3 Wb was incorrect due to a miscalculation of the area used in the formula. The correct area of 8.5 cm² must be applied to obtain the accurate change in flux.

PREREQUISITES
  • Understanding of magnetic flux and its calculation using the formula Φ = B * A * N
  • Familiarity with the concepts of magnetic fields and their units (Tesla)
  • Knowledge of the relationship between magnetic field strength and area in coils
  • Basic understanding of time intervals in physics calculations
NEXT STEPS
  • Review the calculation of magnetic flux using the correct area of 8.5 cm²
  • Learn about Faraday's Law of Electromagnetic Induction and its applications
  • Explore the concept of rate of change of magnetic flux and its significance in physics
  • Investigate the effects of coil turns on magnetic flux calculations
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone involved in solving problems related to magnetic fields and flux changes in coils.

superslow991
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Homework Statement


A 200-loop coil of cross sectional area 8.5 cm2 lies in the plane of the page. An external magnetic field of 0.060 T is directed out of the plane of the page. The external field decreases to 0.020 T in 12 milliseconds.
(a) What is the magnitude of the change in the external magnetic flux enclosed by the coil?

Homework Equations



Φ=BAN

The Attempt at a Solution


I did 200*(8*10^-4)(0.06-0.02) and gotthe answer i got for this problem was 6.8*10^-3
Teacher said it was wrong. Did i mess up somewhere? i calculated it twice and got the same answer so I am not sure how the answer would be wrong?
 
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superslow991 said:

Homework Statement


A 200-loop coil of cross sectional area 8.5 cm2 lies in the plane of the page. An external magnetic field of 0.060 T is directed out of the plane of the page. The external field decreases to 0.020 T in 12 milliseconds.
(a) What is the magnitude of the change in the external magnetic flux enclosed by the coil?

Homework Equations



Φ=BAN

The Attempt at a Solution


I did 200*(8*10^-4)(0.06-0.02) and gotthe answer i got for this problem was 6.8*10^-3
Teacher said it was wrong. Did i mess up somewhere? i calculated it twice and got the same answer so I am not sure how the answer would be wrong?

What is the rate of change of the magnetic field?

Above, as part of your work, you've calculated the total change of magnetic field as part of the answer, but what is the rate of change?

[Edit: see next post. I might have misinterpreted the question.]
 
Last edited:
collinsmark said:
What is the rate of change of the magnetic field?

Above, as part of your work, you've calculated the total change of magnetic field as part of the answer, but what is the rate of change?
Im not following, are you saying to divide the work i did by the time?
 
superslow991 said:
(a) What is the magnitude of the change in the external magnetic flux enclosed by the coil?
Actually on second thought, re-reading the specific question, there might be some misunderstanding for what is being asked.

The way I read the question verbatim [after re-reading it], it isn't asking about rate of flux change, but rather the total change in flux.

Also the use of the word "external" might play a part here. Does the "external" flux depend upon the number of loops in the coil?
 
Last edited:
superslow991 said:
Im not following, are you saying to divide the work i did by the time?
Eventually, perhaps in part (b), I'm guessing that the finding the rate of change of magnetic flux comes into play. And in that case you'll want to divide the total change of flux by the time of the change, to obtain the rate of change.

But given the specific wording of part (a), maybe that's not what your teacher is asking for here.

Instead, for part (a), you might want to focus on the word "external." Does the number of turns in the coil affect this "external" flux?
 
collinsmark said:
Eventually, perhaps in part (b), I'm guessing that the finding the rate of change of magnetic flux comes into play. And in that case you'll want to divide the total change of flux by the time of the change, to obtain the rate of change.

But given the specific wording of part (a), maybe that's not what your teacher is asking for here.

Instead, for part (a), you might want to focus on the word "external." Does the number of turns in the coil affect this "external" flux?
I mean probably not since the flux would be outside the coil? not too sure.
Either that or i was suppose to subtract 0.02 from 0.06?
 
superslow991 said:
I mean probably not since the flux would be outside the coil?

Between you and me, I don't like the way the question was worded.

I think by "external magnetic flux" your teacher was asking you to find the flux, defined by magnetic field strength and and area, of that place in space, whether the coil is actually there or not.

Then find the change from the starting time to the end, to find the change in flux.

I don't like the question because you need the coil to compute the area component, but you ignore the coil for the number of turns it has.

Anyway, that's how I interpret the question after re-reading it.

not too sure.
Either that or i was suppose to subtract 0.02 from 0.06?

Subtracting 0.02 from 0.06 will give you the change in magnetic field strength. You'll still need to throw the area in there somehow to obtain the change in flux.
 
collinsmark said:
Between you and me, I don't like the way the question was worded.

I think by "external magnetic flux" your teacher was asking you to find the flux, defined by magnetic field strength and and area, of that place in space, whether the coil is actually there or not.

Then find the change from the starting time to the end, to find the change in flux.

I don't like the question because you need the coil to compute the area component, but you ignore the coil for the number of turns it has.

Anyway, that's how I interpret the question after re-reading it.
Subtracting 0.02 from 0.06 will give you the change in magnetic field strength. You'll still need to throw the area in there somehow to obtain the change in flux.
yea idk either its asking for flux=BA or flux = BA/t not to sure bout this question
 
superslow991 said:
yea idk either its asking for flux=BA or flux = BA/t not to sure bout this question

Flux is equal to \Phi = \vec B \cdot \vec A.

The rate of change of flux involves dividing the change of flux by the change in time, but I don't think that is what part (a) of the question is asking for.
 
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  • #10
collinsmark said:
Flux is equal to \Phi = \vec B \cdot \vec A.

The rate of change of flux involves dividing the change of flux by the change in time, but I don't think that is what part (a) of the question is asking for.
hmm ok. So what do you think part A is asking for?
 
  • #11
superslow991 said:
hmm ok. So what do you think part A is asking for?
You spell it out. :wink:
 
  • #12
superslow991 said:

Homework Statement


A 200-loop coil of cross sectional area 8.5 cm2 lies in the plane of the page. An external magnetic field of 0.060 T is directed out of the plane of the page. The external field decreases to 0.020 T in 12 milliseconds.
(a) What is the magnitude of the change in the external magnetic flux enclosed by the coil?

Homework Equations



Φ=BAN

The Attempt at a Solution


I did 200*(8*10^-4)(0.06-0.02)
The area was 8.5 cm2. You calculated with 8 cm2.
 
  • #13
ehild said:
The area was 8.5 cm2. You calculated with 8 cm2.
Typo sorry
collinsmark said:
You spell it out. :wink:
idk I mean I thought my equation would solve for the flux but your saying I have to solve for the change of the flux? Went through different calculations just don't know what would be the right answer
 
  • #14
superslow991 said:
idk I mean I thought my equation would solve for the flux but your saying I have to solve for the change of the flux?
No, your original attempt solved for the change in the flux, which I believe is correct (forget about post #2, that was my mistake).

But I don't think you need to include the number of turns in the coil for part (a), given the specific way it was worded.
 
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  • #15
collinsmark said:
No, your original attempt solved for the change in the flux, which I believe is correct (forget about post #2, that was my mistake).

But I don't think you need to include the number of turns in the coil for part (a), given the specific way it was worded.
hmm ok thanks for the help ill try to see what happens today
 

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