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Magnetic flux thorugh a loop of wire

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1. Homework Statement
Griffiths Problem 7.8
A square loop of wire (side a) lies on a table dsiantce s from a very long straight wire, which carries a current I, as shown in teh figure.

Find the flux of B through the loop

2. Homework Equations
Flux of B is given by
[tex] \Phi_{B} = \int \vec{B} \dot d\vec{a} [/tex]


3. The Attempt at a Solution
THe area element is constant
but hte magnetic field is not
For a wire, B at a dsitance r is given by
[tex] \vec{B} = \frac{\mu_{0} I}{2\pi r} \hat{phi} [/tex]

Flux is then
[tex] \Phi_{B} = \int_{s}^{s+a} \frac{\mu_{0} I}{2\pi r} a^2 ds [/tex]

but hte solution says that the area element should be just a, and not a^2 .. why is that???

thanks for help!
 

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but hte solution says that the area element should be just a, and not a^2 .. why is that???
The element of area is "a ds", where "ds" is distance along r: you are treating the area as infinitesimal rectangular strips, parallel to the wire.
 
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2
The element of area is "a ds", where "ds" is distance along r: you are treating the area as infinitesimal rectangular strips, parallel to the wire.
thank you
i get it now
 

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