Magnetic flux through a coil. Field generated by a straight conductor.

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SUMMARY

The discussion focuses on calculating the magnetic flux through a triangular conductor near a long straight conductor carrying a current of 50A. The magnetic flux density (B) at a distance 'a' from the wire is defined by the formula B = μI/2πa. For a distance of 1 cm, B is calculated to be 1 x 10^-3 T. The correct magnetic flux through the triangle is determined to be 7.7 x 10^-8 Wb, emphasizing the necessity of integration to find the magnetic field strength across the triangular area.

PREREQUISITES
  • Understanding of magnetic flux and magnetic flux density
  • Familiarity with the formula B = μI/2πa
  • Basic knowledge of integration techniques
  • Concept of current-carrying conductors and their magnetic fields
NEXT STEPS
  • Study integration techniques for calculating areas under curves
  • Learn about the Biot-Savart Law for magnetic field calculations
  • Explore applications of magnetic flux in electromagnetic theory
  • Investigate the effects of varying current on magnetic fields
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Physics students, electrical engineers, and anyone interested in electromagnetic theory and magnetic field calculations.

Biktor
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Hi! I'm stuck on a problem concerning the magnetic field produced by a long straight conductor:

A triangular piece of conductor (N=1) rests in the vicinity of a long straight conductor with a current I=50A. What is the magnetic flux through the triangle if a=1cm? (See attached file).

My approach was to try to integrate to find how the field from the conductor varies with distance to be able to find the field's strength in that triangle and then multiply it with the area to get the flux, but I'm getting it all wrong.

Is there any general approach to this kind of problem?

The correct answer is 7.7*10^-8 Wb.

Thanks!
 

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I think you are correct in the need to integrate to find the flux through the triangle.
The main piece of information that I can give is that the magnetic flux density (B) at a distance 'a' from a long straight wire is given by:

B = μI/2πa

I am rusty on integration ! but if you can apply this to the area of the triangle it should help
I calculate that B at a distance a=1cm from the wire is 1 x 10^-3T
and B at a distance of 2a = 0.5 x 10^-3T

I have forgotten how to integrate over the area of the triangle... sorry
 

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