Magnetic flux through a loop at two orientations

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The discussion centers on calculating magnetic flux through a circular loop in a magnetic field when the loop is oriented in different ways. For part (a), the loop is parallel to the magnetic field, leading to confusion about the angle; the correct angle is between the magnetic field and the normal to the loop, which is 90 degrees, resulting in zero flux. For part (b), when the loop is perpendicular to the field, the angle is zero, and the flux calculation should reflect that. The participants emphasize the importance of understanding the angle definition in the magnetic flux formula. Resources for further reading on magnetic flux and angles are suggested for clarification.
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Homework Statement



A circular loop of radius 0.10 m is rotating in a uniform external magnetic field of 0.20 T. Find the magnetic flux through the loop due to the external field when the plane of the loop and the magnetic field vector are
(a) parallel.
(b) perpendicular.

Homework Equations


BAcos(theta)

The Attempt at a Solution


i know the answers for this problem but I am having trouble with the direction of the field and area and also the angle between them
For part a- I know its BAcos(90) but why is the angle 90 degrees? I was under the impression if the field and the loop are parrallel the angle should be 0?

For part b- Same thing BAcos(0) i thought the angle was suppose to be 90 degrees if they are perpendicular?

[Mentor note: Thread title adjusted to make it descriptive of the problem]
 
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Consult your textbook or notes to see how the angle θ is defined in the expression BAcosθ.
 
superslow991 said:

Homework Statement


** EDITED ORIGINALPOST
A circular loop of radius 0.10 m is rotating in a uniform external magnetic field of 0.20 T. Find the magnetic flux through the loop due to the external field when the plane of the loop and the magnetic field vector are
(a) parallel.

Homework Equations


BAcos(theta)

The Attempt at a Solution


So i know if the field and the loop are parallel the angle is 0 so i tried

flux = (0.2)*(0.03141)*cos(0) = 0.06282 but the answer is suppose to be 0.

This would be true if the if i did (0.2)*(0.03141)*cos(90) so I am not sure where I am at fault.
 
θ is not the angle between the plane of the loop and B. It's the angle between the normal direction of the loop and B.
 
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TSny said:
θ is not the angle between the plane of the loop and B. It's the angle between the normal direction of the loop and B.
Thanks, is there anyway i can read up on this?
 
superslow991 said:
Thanks, is there anyway i can read up on this?
Of course. The information is readily available if you have a web browser.

Do a web search on the terms of interest, say: "magnetic flux loop angle".
 
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Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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