Magnetic Force and Two Moving Charges

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SUMMARY

The discussion focuses on calculating the magnetic force exerted by a moving charge q' (-4.50 microC) on another moving charge q (7.60 microC) using the formula F_ab = q_b*v_b[(mu_0/(4*pi)]*[(q_a*v_a*u_ab)/r^2]. The calculated magnetic field B_q’ was determined to be 819.2 T, leading to a magnetic force F_q’ of 560.33 N. The direction of the force was concluded to be in the positive y-direction, confirming the application of the right-hand rule in this context.

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  • Understanding of electromagnetic theory, specifically the Lorentz force law.
  • Familiarity with the concepts of point charges and their interactions.
  • Knowledge of vector calculus, particularly unit vectors and their applications in physics.
  • Proficiency in using the constants of physics, such as the permeability of free space (mu_0).
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  • Study the derivation and applications of the Lorentz force law in different reference frames.
  • Learn about the implications of charge motion on magnetic fields, particularly in the context of special relativity.
  • Explore advanced topics in electromagnetism, such as Maxwell's equations and their relevance to moving charges.
  • Investigate practical applications of magnetic forces in engineering, such as in particle accelerators and magnetic confinement.
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Students of physics, particularly those studying electromagnetism, as well as educators and professionals involved in teaching or applying concepts of magnetic forces and charge interactions.

Soaring Crane
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Homework Statement



A pair of point charges, q = 7.60 microC and q' = -4.50 microC, are moving in a reference frame, as shown in the figure, with speeds 9.00×10^4 m/s and v' = 6.40×10^4 m/s.

yf_Figure_28_30.jpg


a. When the point charges are at the locations shown in the figure, what magnetic force does q' exert on q?


b. What is its direction?



Homework Equations



I came across a formula for the magnetic force F_a on b:

F_ab = q_b*v_b[(mu_0/(4*pi)]*[(q_a*v_a*u_ab)/r^2]

where u_ab = unit vector directed from q_a to q_b

Shortened F_ab = q_b*v_b*B_a??


The Attempt at a Solution



I really don’t know if I used the formula properly, so:

Magnitude B_q’ = [mu_0/(4*pi)]*[(q_a*v_b*u_ab)/r^2 = [mu_0/(4*pi)]*[(q_a*v_b*r_ab)/r^3

= (1.0*10^-7)*(32000 m^2/s)*(4.50*10^-6 C)/[0.500m]^3
= 819.2 T ??

Magnitude F_q’ on q = q*v_q*B_q’ = ((7.60*10^-6 C)*(9.00*10^4 m/s)*819.2 T) = 560.33 N ?

Will the force’s direction be in the positive(+) y-direction?

Thanks.
 
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Can anyone please inform me if the method/direction is correct?

Any advice is appreciated.

Thanks again.
 

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