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Magnetic Forces on Charged Particles

  1. Feb 24, 2009 #1
    1. The problem statement, all variables and given/known data

    A particle with a charge of +8.4 µC and a speed of 55 m/s enters a uniform magnetic field whose magnitude is 0.30 T. For each of the cases in the drawing, find the magnitude and direction of the magnetic force on the particle.

    21_02.gif

    2. Relevant equations

    B = F / [q(VsinΘ)]

    3. The attempt at a solution

    Ok, for case (a) I tried the following:

    - 30 = F / [8.4*10^6(55sin30)]
    - 30 = F / 27.5
    - 30 * 27.5 = F
    - F= 825 N

    Where am I going wrong? Thanks!
     
  2. jcsd
  3. Feb 24, 2009 #2

    LowlyPion

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    Homework Helper

    Welcome to PF.

    Remember these are vectors and the Force vector will be in what direction?

    And it is determined by what scalar operation?
     
  4. Feb 24, 2009 #3

    LowlyPion

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    Also note your B field is .3T
     
  5. Feb 24, 2009 #4
    Ah, of course. I'm not sure how I kept reading B as "30" rather than ".3" lol.

    So the actual answer would be 6.93E-5.

    Thanks!
     
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