Magnetic Moment- Spin System - Probability

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SUMMARY

The discussion focuses on calculating the probability PN(m) for a spin system consisting of 30 localized particles with a spin quantum number of s = ½ and a magnetic moment µ0. Two scenarios are analyzed: one without a magnetic field (p = q = 1/2) and another with a magnetic field (p = 0.7; q = 0.3). The relationship between spin angular momentum and magnetic moment is established through the formulas: Spin Angular Momentum = [h√{S*(S+1)}]/2π and Magnetic Moment = √{4S*(S+1)}. The participants seek clarification on the definitions of m and M in relation to the magnetic moment.

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  • Understanding of spin quantum numbers in quantum mechanics
  • Familiarity with the concepts of magnetic moment and spin angular momentum
  • Basic knowledge of probability theory as applied to quantum systems
  • Ability to interpret and manipulate mathematical formulas related to quantum mechanics
NEXT STEPS
  • Study the derivation of the formulas for spin angular momentum and magnetic moment
  • Learn about the statistical mechanics of spin systems and their probabilities
  • Explore the implications of magnetic fields on spin systems and their magnetic moments
  • Investigate the application of these concepts in quantum computing and magnetic resonance imaging (MRI)
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Students and researchers in quantum mechanics, physicists working with magnetic materials, and anyone interested in the statistical properties of spin systems in physics.

VVS
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Homework Statement



Spin-system:
A spin-system has N = 30 localized particles with spin quantum number s = ½ and magnetic moment µ0. m = M/µ0 is the magnetic moment M in vertical direction (ms = +½) in units of µ0.
Calculate the probability PN(m) for the total magnetic moment M to achieve in vertical direction the value m
a) Without magnetic field (p = q =1/2) and
b) With magnetic field (p = 0,7; q = 0,3),
under the assumption that p und q = 1-p are the probabilities for ms = +1/2 and ms = -1/2, respectively.
Draw the values for PN(m) in both cases.


Homework Equations



all given in 1.

The Attempt at a Solution



View attachment Problem_Sheet_1_Exercise_3.pdf

I just don't know how the spin is related to the magnetic moment.
Is m=1/2 or -1/2 or M=1/2 or -1/2
 
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VVS said:

Homework Statement



Spin-system:
A spin-system has N = 30 localized particles with spin quantum number s = ½ and magnetic moment µ0. m = M/µ0 is the magnetic moment M in vertical direction (ms = +½) in units of µ0.
Calculate the probability PN(m) for the total magnetic moment M to achieve in vertical direction the value m
a) Without magnetic field (p = q =1/2) and
b) With magnetic field (p = 0,7; q = 0,3),
under the assumption that p und q = 1-p are the probabilities for ms = +1/2 and ms = -1/2, respectively.
Draw the values for PN(m) in both cases.

Homework Equations



all given in 1.

The Attempt at a Solution



View attachment 56430

I just don't know how the spin is related to the magnetic moment.
Is m=1/2 or -1/2 or M=1/2 or -1/2

Hint: What is the formula for "spin angular momentum" ?
What is the formula for "magnetic moment" ?
Once you know the two, you can see the obvious relation.
 
Hi,

Thanks for the hint. I checked online, but I can't find any formulae for sping angular momentum and magnetic moment.

Could you please give me another hint?

thank you
 
VVS said:
Hi,

Thanks for the hint. I checked online, but I can't find any formulae for sping angular momentum and magnetic moment.

Could you please give me another hint?

thank you

Spin angular momentum = [h√{S*(S+1)}]/2π

Magnetic moment = √{4S*(S+1)}

Now can you carry out further ?

S is spin quantum number.
 
Thanks,

From those two formulae it is clear that Spin Angular Momentum = h/(4*pi)*magnetic moment.

But I am not sure how this is supposed to help me with the problem. The sentence I didn't understand was:

m = M/µ0 is the magnetic moment M in vertical direction (ms = +½) in units of µ0. Calculate the probability PN(m) for the total magnetic moment M to achieve in vertical direction the value m under the assumption that p und q = 1-p are the probabilities for ms = +1/2 and ms = -1/2, respectively.

Is M=±1/2 or M/μ0 = ±1/2?
 
VVS said:
Thanks,

From those two formulae it is clear that Spin Angular Momentum = h/(4*pi)*magnetic moment.

But I am not sure how this is supposed to help me with the problem. The sentence I didn't understand was:

m = M/µ0 is the magnetic moment M in vertical direction (ms = +½) in units of µ0. Calculate the probability PN(m) for the total magnetic moment M to achieve in vertical direction the value m under the assumption that p und q = 1-p are the probabilities for ms = +1/2 and ms = -1/2, respectively.

Is M=±1/2 or M/μ0 = ±1/2?

I cannot understand this:

A spin-system has N = 30 localized particles with spin quantum number s = ½ and magnetic moment µ0. m = M/µ0 is the magnetic moment M in vertical direction (ms = +½) in units of µ0.

µ0 is magnetic moment of 30 localized particles, fine. But what is m?
I guess that M being vertical component, we have µ0 sinθ=M. This means m=sinθ. What is ms? In my textbook, ms is spin quantum number, but here already its denoted by S. Might be that you should contact other HHs.
 

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