Magnetic Moment- Spin System - Probability

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Homework Help Overview

The discussion revolves around a spin-system with 30 localized particles, each having a spin quantum number of ½ and a magnetic moment denoted as µ0. Participants are tasked with calculating the probability PN(m) for the total magnetic moment M to achieve specific values in a vertical direction under two scenarios: without a magnetic field and with a magnetic field, where probabilities for spin states are defined. The relationship between spin and magnetic moment is a focal point of inquiry.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants express uncertainty about how spin relates to magnetic moment and question the definitions of variables such as m, M, and ms. Some seek clarification on the formulas for spin angular momentum and magnetic moment, while others attempt to derive relationships between these quantities.

Discussion Status

Several participants have provided hints and formulas related to spin angular momentum and magnetic moment, yet there remains a lack of clarity regarding the definitions and implications of the variables involved. The discussion is ongoing, with participants actively seeking further clarification and guidance.

Contextual Notes

Participants note confusion regarding the definitions of m, M, and ms, as well as the implications of the given probabilities for spin states. There is an acknowledgment of potential discrepancies in terminology as used in different sources.

VVS
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Homework Statement



Spin-system:
A spin-system has N = 30 localized particles with spin quantum number s = ½ and magnetic moment µ0. m = M/µ0 is the magnetic moment M in vertical direction (ms = +½) in units of µ0.
Calculate the probability PN(m) for the total magnetic moment M to achieve in vertical direction the value m
a) Without magnetic field (p = q =1/2) and
b) With magnetic field (p = 0,7; q = 0,3),
under the assumption that p und q = 1-p are the probabilities for ms = +1/2 and ms = -1/2, respectively.
Draw the values for PN(m) in both cases.


Homework Equations



all given in 1.

The Attempt at a Solution



View attachment Problem_Sheet_1_Exercise_3.pdf

I just don't know how the spin is related to the magnetic moment.
Is m=1/2 or -1/2 or M=1/2 or -1/2
 
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VVS said:

Homework Statement



Spin-system:
A spin-system has N = 30 localized particles with spin quantum number s = ½ and magnetic moment µ0. m = M/µ0 is the magnetic moment M in vertical direction (ms = +½) in units of µ0.
Calculate the probability PN(m) for the total magnetic moment M to achieve in vertical direction the value m
a) Without magnetic field (p = q =1/2) and
b) With magnetic field (p = 0,7; q = 0,3),
under the assumption that p und q = 1-p are the probabilities for ms = +1/2 and ms = -1/2, respectively.
Draw the values for PN(m) in both cases.

Homework Equations



all given in 1.

The Attempt at a Solution



View attachment 56430

I just don't know how the spin is related to the magnetic moment.
Is m=1/2 or -1/2 or M=1/2 or -1/2

Hint: What is the formula for "spin angular momentum" ?
What is the formula for "magnetic moment" ?
Once you know the two, you can see the obvious relation.
 
Hi,

Thanks for the hint. I checked online, but I can't find any formulae for sping angular momentum and magnetic moment.

Could you please give me another hint?

thank you
 
VVS said:
Hi,

Thanks for the hint. I checked online, but I can't find any formulae for sping angular momentum and magnetic moment.

Could you please give me another hint?

thank you

Spin angular momentum = [h√{S*(S+1)}]/2π

Magnetic moment = √{4S*(S+1)}

Now can you carry out further ?

S is spin quantum number.
 
Thanks,

From those two formulae it is clear that Spin Angular Momentum = h/(4*pi)*magnetic moment.

But I am not sure how this is supposed to help me with the problem. The sentence I didn't understand was:

m = M/µ0 is the magnetic moment M in vertical direction (ms = +½) in units of µ0. Calculate the probability PN(m) for the total magnetic moment M to achieve in vertical direction the value m under the assumption that p und q = 1-p are the probabilities for ms = +1/2 and ms = -1/2, respectively.

Is M=±1/2 or M/μ0 = ±1/2?
 
VVS said:
Thanks,

From those two formulae it is clear that Spin Angular Momentum = h/(4*pi)*magnetic moment.

But I am not sure how this is supposed to help me with the problem. The sentence I didn't understand was:

m = M/µ0 is the magnetic moment M in vertical direction (ms = +½) in units of µ0. Calculate the probability PN(m) for the total magnetic moment M to achieve in vertical direction the value m under the assumption that p und q = 1-p are the probabilities for ms = +1/2 and ms = -1/2, respectively.

Is M=±1/2 or M/μ0 = ±1/2?

I cannot understand this:

A spin-system has N = 30 localized particles with spin quantum number s = ½ and magnetic moment µ0. m = M/µ0 is the magnetic moment M in vertical direction (ms = +½) in units of µ0.

µ0 is magnetic moment of 30 localized particles, fine. But what is m?
I guess that M being vertical component, we have µ0 sinθ=M. This means m=sinθ. What is ms? In my textbook, ms is spin quantum number, but here already its denoted by S. Might be that you should contact other HHs.
 

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