- #1
garyman
- 19
- 0
Hi,
I'm slightly confused about how to prove that:
[tex]\chi[/tex]=[tex]\vartheta[/tex]<M>/[tex]\vartheta[/tex]H
is equal to...
[tex]\chi[/tex]=(<M2>-<M>2 )/ T
I've expressed <M> as [tex]\sum[/tex]Msexp(-E/kBT) /
[tex]\sum[/tex]exp(-E/kBT)
and know that E=-J[tex]\sum[/tex]SiSj-H[tex]\sum[/tex]Si
But seem to get lost in the differentiation. I am going aobut this the correct way?
I'm slightly confused about how to prove that:
[tex]\chi[/tex]=[tex]\vartheta[/tex]<M>/[tex]\vartheta[/tex]H
is equal to...
[tex]\chi[/tex]=(<M2>-<M>2 )/ T
I've expressed <M> as [tex]\sum[/tex]Msexp(-E/kBT) /
[tex]\sum[/tex]exp(-E/kBT)
and know that E=-J[tex]\sum[/tex]SiSj-H[tex]\sum[/tex]Si
But seem to get lost in the differentiation. I am going aobut this the correct way?