Magnitude and angle of particle direction-

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SUMMARY

The discussion centers on calculating the net force and direction of a 0.26 kg particle moving in an xy plane, defined by the equations x(t) = -10 + 2t - 3t³ and y(t) = 29 + 3t - 4t². At t = 2.0 s, the participant initially calculated the net force magnitude as 31.04 N and angles of 146.309° and 123.69° for the net force and direction of travel, respectively. However, these calculations were identified as incorrect, prompting a request for detailed work to identify errors in the approach.

PREREQUISITES
  • Understanding of calculus, specifically differentiation
  • Knowledge of Newton's second law of motion
  • Familiarity with vector components in physics
  • Ability to analyze motion in two dimensions
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  • Review the principles of differentiation in the context of motion equations
  • Study Newton's second law and its application to particle motion
  • Learn how to resolve vectors into components and calculate net forces
  • Explore the concept of angle measurement in physics, particularly in relation to coordinate systems
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Students studying physics, particularly those focusing on mechanics and motion analysis, as well as educators looking to clarify concepts related to particle dynamics and force calculations.

physics131
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A 0.26 kg particle moves in an xy plane according to x(t) = - 10 + 2 t - 3 t3(t cubed) and y(t) = 29 + 3 t - 4 t2 (t squared), with x and y in meters and t in seconds. At t = 2.0 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?


To solve this question I differentiated the two equations given and also found the accceleration.I then subbed in my value for t (t=2). After some more calculations I got 31.04 as my answer for part (a)146.309 degrees for part (b) and 123.69 degrees for part (c)
These answers are wrong and i can't understand where I am going wrong.
Any help with this problem would be much appreciated!
 
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physics131 said:
A 0.26 kg particle moves in an xy plane according to x(t) = - 10 + 2 t - 3 t3(t cubed) and y(t) = 29 + 3 t - 4 t2 (t squared), with x and y in meters and t in seconds. At t = 2.0 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?


To solve this question I differentiated the two equations given and also found the accceleration.I then subbed in my value for t (t=2). After some more calculations I got 31.04 as my answer for part (a)146.309 degrees for part (b) and 123.69 degrees for part (c)
These answers are wrong and i can't understand where I am going wrong.
Any help with this problem would be much appreciated!

Yes, your answers are wrong. But we can not do anything if you do not show your work in detail.

ehild
 

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