1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Magnitude and Direction of Electric Field

  1. Sep 14, 2009 #1
    1. The problem statement, all variables and given/known data
    Two point charges are placed on the y-axis. One is +3.0 C and located at position (0, 2 m), the other is -2.0 C and located at the origin. Use the diagram to find the magnitude and direction of the electric field and the force on a +1.0 x 10-9 C test charge placed in the following locations.
    a. (0, 1.0 m)
    b. (0, -2.0 m)
    c. (1.0m, 0)

    2. Relevant equations

    E= kq/(r^2)

    3. The attempt at a solution
    So for part a:
    F= (K(3x10^-6)/(1^2) + K(2x10-6)/(1^2))
    E= F/(test charge)

    Same for part b, but the radius is different.
    My question is how do I get part C?
    I calculated the force between the -2uc charge and point C, but how do I get the force between the +3uc charge and point C?

    Do I need to find the angle?
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     

    Attached Files:

  2. jcsd
  3. Sep 14, 2009 #2

    rl.bhat

    User Avatar
    Homework Helper

    Find the distance between points ( 0, 2) and (1,0).
    Find field at (1,0) due to + 3μC and - 2μC.
    Resolve the field due to +3μC into x and y components.
    Find the net x component and find the resultant with y component.
     
  4. Sep 15, 2009 #3
    Thank you for the reply, i'll try this out tomorrow.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Magnitude and Direction of Electric Field
Loading...