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Magnitude and direction of impulse of baseball

  1. Oct 21, 2009 #1
    1. The problem statement, all variables and given/known data
    A baseball player hits a baseball (m = 0.145 kg) as shown in the figure below. The ball is initially traveling horizontally with speed of 35 m/s. The batter hits a fly ball as shown, with a speed vf = 51 m/s. What is the magnitude and direction of the impulse imparted on the ball. The initial velocity is going along the x axis in the negative direction and the final velocity is going at a 45 degree angle in the first quadrant.


    2. Relevant equations



    3. The attempt at a solution First I had the initial velocity at -35. The final velocity I had the final velocity* cos theta. I don't know where to go from here.
     
  2. jcsd
  3. Oct 21, 2009 #2

    Doc Al

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    Staff: Mentor

    You need to consider both x (horizontal) and y (vertical) components of the velocity. What's the y component of the final velocity?

    Once you have that, how would you compute the impulse?
     
  4. Oct 21, 2009 #3
    The y component is final velocity* sin theta. I have the x component for both final a initial velocities and the y component for the final velocity. The y component for the initial will be just the -35m/s. How do I add them together to get the magnitude?
     
  5. Oct 21, 2009 #4

    Doc Al

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    OK.
    OK.
    No. (It's thrown horizontally.)
    Once you get the final components of the impulse, then you can find the magnitude using Pythagorus (like you would with any other vector).

    But before you do anything, how will you calculate the impulse? How does it relate to the velocities?
     
  6. Oct 21, 2009 #5
    Impulse is dp=mv_f-mv_i. I have the final velocity* cos theta+ final velocity *sin theta+ initial velocity. Is this right?
     
  7. Oct 21, 2009 #6

    Doc Al

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    OK. Impulse = Δp. But you need to find the x and y components of the Impulse separately:
    Impulsex = m(Vfx -Vix)
    Impulsey = m(Vfy - Viy)
     
  8. Oct 21, 2009 #7
    Thanks I got the answer. I knew how to get the magnitude but got stuck with how to set it up after finding the components.
     
  9. Oct 21, 2009 #8
    I have one more problem it asks for the direction of the impulse imparted to the bat. I have the magnitude but don't know how would I find the direction.
     
  10. Oct 21, 2009 #9

    Doc Al

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    The impulse that the ball imparts to the bat is equal and opposite to the impulse the bat imparts to the ball. (This is from Newton's 3rd law.)
     
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