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Magnitude and Direction of Magnetic Field

  • Thread starter hardwork
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  • #1
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Homework Statement


Two long straight wires each carry 3.4 A of current and are crossed, as shown in the figure. If Dh=12.0cm and Dv=6.0cm, what is the magnitude and direction of the magnetic field at A? Figure: http://i41.tinypic.com/4louv6.jpg"


Homework Equations


B=(Mu)(I)/(2pie)(r)


The Attempt at a Solution


B = [(4pie x 10^-7 Tm/A)(3.4A)]/(2pie) x (1/6.0cm - 1/12.0cm)
B = 5.7 x 10^-8 T out of page

Would someone be able to please check if that is the correct answer? Thank you!
 
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Answers and Replies

  • #2
Doc Al
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B = [(4pie x 10^-7 Tm/A)(3.4A)]/(2pie) x (1/6.0cm - 1/12.0cm)
B = 5.7 x 10^-8 T out of page
Almost. Express those distances in standard units.
 
  • #3
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Oh, right. Thank you!

B = 5.7 x 10^-6 T out of page
 
  • #4
Doc Al
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44,882
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