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Magnitude and Direction of Magnetic Field

  1. Apr 12, 2009 #1
    1. The problem statement, all variables and given/known data
    Two long straight wires each carry 3.4 A of current and are crossed, as shown in the figure. If Dh=12.0cm and Dv=6.0cm, what is the magnitude and direction of the magnetic field at A? Figure: http://i41.tinypic.com/4louv6.jpg"


    2. Relevant equations
    B=(Mu)(I)/(2pie)(r)


    3. The attempt at a solution
    B = [(4pie x 10^-7 Tm/A)(3.4A)]/(2pie) x (1/6.0cm - 1/12.0cm)
    B = 5.7 x 10^-8 T out of page

    Would someone be able to please check if that is the correct answer? Thank you!
     
    Last edited by a moderator: Apr 24, 2017
  2. jcsd
  3. Apr 12, 2009 #2

    Doc Al

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    Staff: Mentor

    Almost. Express those distances in standard units.
     
  4. Apr 12, 2009 #3
    Oh, right. Thank you!

    B = 5.7 x 10^-6 T out of page
     
  5. Apr 12, 2009 #4

    Doc Al

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    Staff: Mentor

    Good!
     
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