Two long straight wires each carry 3.4 A of current and are crossed, as shown in the figure. If Dh=12.0cm and Dv=6.0cm, what is the magnitude and direction of the magnetic field at A? Figure: http://i41.tinypic.com/4louv6.jpg"
The Attempt at a Solution
B = [(4pie x 10^-7 Tm/A)(3.4A)]/(2pie) x (1/6.0cm - 1/12.0cm)
B = 5.7 x 10^-8 T out of page
Would someone be able to please check if that is the correct answer? Thank you!
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