Magnitude & Direction of V Vector

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SUMMARY

The magnitude of vector V, given Vx = 6.80 units and Vy = -7.40 units, is calculated using the formula V magnitude = √(Vx² + Vy²), resulting in 10 units. The direction of vector V is determined using the tangent function, where tan θ = Vy/Vx, yielding θ = -47.4 degrees below the x-axis. This analysis confirms the calculations are accurate and provides a clear understanding of vector magnitude and direction.

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  • Familiarity with the Pythagorean theorem for calculating magnitudes
  • Knowledge of trigonometric functions, specifically tangent
  • Ability to interpret angles in standard position
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Homework Statement


If Vx = 6.80 units and vy = -7.40 units, determine the magnitude and direction of V-> (vector, the arrow is above the V).

Homework Equations

and

The Attempt at a Solution


Should we use the following:
V magnitude = √ ( Vx^2 + Vy ^2) = √ (6.80^2 + (-7.40)^2) = 10 units
and for the direction: tan θ = Vy/Vx = (-7.40)/6.80 = -1.1
θ= -47.4 degrees below the x axis.

Would this be correct?

Thanks!
 
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Looks correct to me.
 
Thanks a lot!
 

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