Finding magnitude and direction of vector with Vx = 6.80 and Vy = -7.40

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Homework Statement


If Vx = 6.80 units and vy = -7.40 units, determine the magnitude and direction of V-> (vector, the arrow is above the V).

Homework Equations

and

The Attempt at a Solution


Should we use the following:
V magnitude = √ ( Vx^2 + Vy ^2) = √ (6.80^2 + (-7.40)^2) = 10 units
and for the direction: tan θ = Vy/Vx = (-7.40)/6.80 = -1.1
θ= -47.4 degrees below the x axis.

Would this be correct?

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