- #1
roam
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Homework Statement
If Q = 80 nC, a = 3.0 m, and b = 4.0 m in the figure, what is the magnitude of the electric field at point P?
[PLAIN]http://img829.imageshack.us/img829/9703/72660756.gif
Homework Equations
[tex]\vec{E}=k_e \frac{q}{r^2}\hat{r}[/tex]
The Attempt at a Solution
The magnitude of the electric field at P due to the first charge is:
[tex]E_1 = (8.9 \times 10^9) \frac{(2 \times 80) \times 10^{-9}}{(4^2+3^2)}=56.96[/tex]
due to the second charge it's:
[tex]E_2 = (8.9 \times 10^9) \frac{(-80) \times 10^{-9}}{(4^2)} = - 44.5[/tex]
And due to charge 3:
[tex]E_3 = (8.9 \times 10^9) \frac{(2 \times 80) \times 10^{-9}}{(4^2+3^2)}=56.96[/tex]
The total magnitude of the electric field at P would be: [tex]56.96-44.5+56.96 = 69.3[/tex]
But the correct answer is 47 N/C. Could anyone please show me what is wrong with my calculations?
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