Magnitude of electric field, is this right?

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SUMMARY

The magnitude of the electric field can be calculated using the formula E = F/q, where F is the force and q is the charge. Given a charge of 1.65 x 10^-6 C and an acceleration of 6.33 x 10^7 m/s^2, the force can be determined using F = ma. The correct calculation yields an electric field strength of 14.9 N/C, confirming option C as the accurate answer. Other options presented do not align with the calculations based on the provided data.

PREREQUISITES
  • Understanding of Newton's second law of motion (F = ma)
  • Basic knowledge of electric fields and charge (E = F/q)
  • Familiarity with scientific notation and unit conversions
  • Concept of acceleration in physics
NEXT STEPS
  • Study the relationship between force, mass, and acceleration in physics
  • Learn about electric field calculations and their applications
  • Explore the implications of charge and electric forces in electrostatics
  • Investigate the effects of varying charge and mass on electric field strength
USEFUL FOR

Physics students, educators, and anyone interested in understanding electric fields and the forces acting on charged particles.

staceface
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a 1.65 x 10^-6 C charge experiences an acceleration of 6.33 x 10^7 m/s^2 in an electric field. What is the magnitude of the electric field?


E = F/q

F = ma ?

So if F = ma then mass is not given and then E is correct.

A. 3.84 x 10^16
B. 1.65 x 10^-9
C. 14.9 N/C
D 2.67 x 10^-19
E. more info is needed to solve
 
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I would have to agree with you.
 

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