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The Earth’s magnetic field at a certain location in the UK has a magnitude of 48 μT and is directed at 66° below the horizontal.

a)Determine the magnitude of the flux of the Earth’s magnetic field through a

wedding ring of diameter 2.2 cm when the ring is held in a horizontal plane.

ok so i have used the equation B*A*cos(theta)

the only thing slowing me down is the use of 48 μT . Im not sure how to work this into the equation. I am led to believe that μ is the permuabilty of space so not sure what is meant by μT for the magnetic field of the Earth. I have probably overlooked it in my text and cant find the relevant part now.

Also i am guessing that 66° below the horizontal is equal to 66° from the perpendicular.