How to Find the "Net Change Ring Area Ratio" for the Zeeman Effect

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SUMMARY

The discussion focuses on calculating the "Net Change Ring Area Ratio" (##\delta/\Delta##) for the Zeeman Effect using a Fabry-Perot interferometer. The key equations provided include ##\delta_{1st \; order} = {d^2}_{2nd \; ring} - {d^2}_{1st \; ring}## for the first order and ##\Delta_{Between \; orders \; 1 \; and \; 2} = {d^2}_{central \; ring \; in \; order \; 2} - {d^2}_{central \; ring \; in \; order \; 1}##. Participants discussed the need to find six values of ##\frac{\delta}{\Delta}## corresponding to different magnetic field strengths, with a focus on the accuracy of measurements and the implications of varying current on the observed ring patterns. The central spot's diameter and its influence on calculations were also debated.

PREREQUISITES
  • Understanding of the Zeeman Effect and its implications in spectroscopy.
  • Familiarity with the Fabry-Perot interferometer and its operational principles.
  • Knowledge of basic optics, particularly interference patterns and ring formation.
  • Ability to perform calculations involving squares of diameters and averages.
NEXT STEPS
  • Research "Fabry-Perot interferometer applications in spectroscopy" to deepen understanding of the setup.
  • Study "Zeeman Effect experimental setups" to explore different methods of observing spectral lines.
  • Learn about "data analysis techniques for optical measurements" to improve accuracy in calculations.
  • Investigate "ring diameter measurement techniques" to enhance precision in determining ##\delta## and ##\Delta## values.
USEFUL FOR

Physicists, optical engineers, and students conducting experiments related to the Zeeman Effect and interference patterns in spectroscopy will benefit from this discussion.

  • #31
Note on the above: If you draw the best fit line that passes through the origin, and use the slope, the answer won't be very much different than the answer you get when you put in the values of ## \frac{\delta}{\Delta}=.3 ## and ## B=.8 ##.
(If you draw the line through the origin and through the point with ## \frac{\delta}{\Delta}=.3 ## and ## B=.8 ##, and compute the slope, you get the same answer as by plugging in the values).
 
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