Make a conjecture about y = ax+b

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The discussion revolves around making a conjecture about the linear function y = ax + b, specifically regarding the ratio of the x-coordinate to the y-coordinate. Participants explore how to derive the ratio x/y, aiming to show that it equals a/1, but often arriving at x/y = 1/(a+b). They discuss the method of finding the slope of the shortest line from the origin to the line y = ax + b, emphasizing the need to differentiate the distance function. The conversation highlights the importance of algebraic manipulation and understanding the relationship between the coefficients and the resulting ratios. Ultimately, the goal is to prove the conjecture through algebraic methods while clarifying the underlying concepts.
  • #31
5ymmetrica1 said:
Actually I've been away from my studies for a long time due to some health issues and have been struggling to get myself back to where I was 6 months ago, I have finals coming up too which is worrying!

Is my last post correct?

No, it's not. x+(a^2)x=(1+a^2)x. Don't you see why? Follow tiny-tim's clue about 'distributive law'.
 
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  • #32
Dick said:
No, it's not. x+(a^2)x=(1+a^2)x. Don't you see why? Follow tiny-tim's clue about 'distributive law'.

Thanks, yes I understand why now.

so x = -ab / (1+a2) ?
 
  • #33
5ymmetrica1 said:
so x = -ab / (1+a2) ?

yup! :smile:

so y = … ?

and the slope = … ? :wink:
 
  • #34
tiny-tim said:
yup! :smile:

so y = … ?

and the slope = … ? :wink:

y = a(-ab/(1+a2)) + b

I think this works? But I'm still not sure how I get -a from this answer
 
  • #35
5ymmetrica1 said:
y = a(-ab/(1+a2)) + b

I think this works? But I'm still not sure how I get -a from this answer

you seem to be frightened by algebra

grit your teeth and expand a(-ab/(1+a2)) and you should see how -a pans out :wink:
 
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  • #36
yeah I worked it out today, I think this problem just got the better of me this week lol.

Thanks for your help everyone!
 
  • #37
good! :smile:

but since you need the practice, now try it another way …

your professor told you to find the the slope (let's call it "k") by finding the distance as a function of x, and to differentiate wrt x

instead, try finding the distance as a function of k, and differentiating wrt k (which will give you k directly, and may be quicker)

ie for the slope y = kx, find the coordinates where it intersects y = ax + b (both as a function of k), and then minimise that

to practise your algebra, show us what you get :smile:

(and which method do you think is quicker?)​
 

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