Make a conjecture about y = ax+b

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SUMMARY

The discussion revolves around making a conjecture about the linear function y = ax + b, specifically focusing on the ratio of the x-coordinate to the y-coordinate. Participants explore the relationship between the coefficients and the resulting ratios, concluding that the ratio x/y approaches a/1 as the values of x and y are derived from the function. The conversation highlights the use of calculus to find the minimum distance from the origin to the line, ultimately leading to the conjecture that the ratio of x to y is equal to the value of 'a' in the equation.

PREREQUISITES
  • Understanding of linear functions, specifically y = ax + b
  • Basic knowledge of calculus, including differentiation
  • Familiarity with algebraic manipulation and the distributive law
  • Concept of distance in a Cartesian plane, particularly distance from a point to a line
NEXT STEPS
  • Study the concept of minimizing distance in calculus, focusing on distance functions
  • Learn about the geometric interpretation of linear functions and their slopes
  • Explore the relationship between coefficients in linear equations and their graphical representations
  • Practice algebraic manipulation techniques to simplify expressions involving variables and constants
USEFUL FOR

Students studying algebra and calculus, particularly those working on linear functions and optimization problems. This discussion is beneficial for anyone looking to deepen their understanding of the relationships between variables in linear equations.

  • #31
5ymmetrica1 said:
Actually I've been away from my studies for a long time due to some health issues and have been struggling to get myself back to where I was 6 months ago, I have finals coming up too which is worrying!

Is my last post correct?

No, it's not. x+(a^2)x=(1+a^2)x. Don't you see why? Follow tiny-tim's clue about 'distributive law'.
 
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  • #32
Dick said:
No, it's not. x+(a^2)x=(1+a^2)x. Don't you see why? Follow tiny-tim's clue about 'distributive law'.

Thanks, yes I understand why now.

so x = -ab / (1+a2) ?
 
  • #33
5ymmetrica1 said:
so x = -ab / (1+a2) ?

yup! :smile:

so y = … ?

and the slope = … ? :wink:
 
  • #34
tiny-tim said:
yup! :smile:

so y = … ?

and the slope = … ? :wink:

y = a(-ab/(1+a2)) + b

I think this works? But I'm still not sure how I get -a from this answer
 
  • #35
5ymmetrica1 said:
y = a(-ab/(1+a2)) + b

I think this works? But I'm still not sure how I get -a from this answer

you seem to be frightened by algebra

grit your teeth and expand a(-ab/(1+a2)) and you should see how -a pans out :wink:
 
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  • #36
yeah I worked it out today, I think this problem just got the better of me this week lol.

Thanks for your help everyone!
 
  • #37
good! :smile:

but since you need the practice, now try it another way …

your professor told you to find the the slope (let's call it "k") by finding the distance as a function of x, and to differentiate wrt x

instead, try finding the distance as a function of k, and differentiating wrt k (which will give you k directly, and may be quicker)

ie for the slope y = kx, find the coordinates where it intersects y = ax + b (both as a function of k), and then minimise that

to practise your algebra, show us what you get :smile:

(and which method do you think is quicker?)​
 

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