Make a conjecture about y = ax+b

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Homework Help Overview

The discussion revolves around making a conjecture about the linear function y = ax + b, specifically focusing on the ratio of the x-coordinate to the y-coordinate. Participants are exploring the implications of this ratio and how it relates to the parameters of the function.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various attempts to derive the ratio x/y in relation to the slope 'a' of the function. There are questions about the relevance of previous problems and how they connect to the current conjecture. Some participants suggest examining specific y-values for different x-values to observe patterns.

Discussion Status

The conversation is ongoing, with participants providing insights and questioning each other's reasoning. Some have offered guidance on how to approach the algebraic proof of the conjecture, while others express confusion about the mathematical steps involved. There is no clear consensus yet, but the discussion is productive.

Contextual Notes

Participants mention that they are required to prove their conjecture with algebra, and there are references to previous problems that may influence their current understanding. Some express uncertainty about the question's requirements and the relationship between the original function and the conjecture.

  • #31
5ymmetrica1 said:
Actually I've been away from my studies for a long time due to some health issues and have been struggling to get myself back to where I was 6 months ago, I have finals coming up too which is worrying!

Is my last post correct?

No, it's not. x+(a^2)x=(1+a^2)x. Don't you see why? Follow tiny-tim's clue about 'distributive law'.
 
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  • #32
Dick said:
No, it's not. x+(a^2)x=(1+a^2)x. Don't you see why? Follow tiny-tim's clue about 'distributive law'.

Thanks, yes I understand why now.

so x = -ab / (1+a2) ?
 
  • #33
5ymmetrica1 said:
so x = -ab / (1+a2) ?

yup! :smile:

so y = … ?

and the slope = … ? :wink:
 
  • #34
tiny-tim said:
yup! :smile:

so y = … ?

and the slope = … ? :wink:

y = a(-ab/(1+a2)) + b

I think this works? But I'm still not sure how I get -a from this answer
 
  • #35
5ymmetrica1 said:
y = a(-ab/(1+a2)) + b

I think this works? But I'm still not sure how I get -a from this answer

you seem to be frightened by algebra

grit your teeth and expand a(-ab/(1+a2)) and you should see how -a pans out :wink:
 
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  • #36
yeah I worked it out today, I think this problem just got the better of me this week lol.

Thanks for your help everyone!
 
  • #37
good! :smile:

but since you need the practice, now try it another way …

your professor told you to find the the slope (let's call it "k") by finding the distance as a function of x, and to differentiate wrt x

instead, try finding the distance as a function of k, and differentiating wrt k (which will give you k directly, and may be quicker)

ie for the slope y = kx, find the coordinates where it intersects y = ax + b (both as a function of k), and then minimise that

to practise your algebra, show us what you get :smile:

(and which method do you think is quicker?)​
 

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