Making a definite integral equal and indefinite integral?

[Saracen Rue]

I have a calculator which allows me to sketch indefinite integrals - it assumes c = 0. However, when I try to use Desmos Online Graphing Calculator, it won't let me do this with it's integral function. It keeps trying to make me use definite integrals.

I know that ∫(a,b,f(x)dx = F(a) - F(b), so I was wondering if it's possible to define a and b so that the resulting definite integral equals the indefinite integral (where c = 0)

 

[andrewkirk]

How does it sketch the definite integrals? If it sketches the curve of $F(x)$ vs $x$ where $F(x)$ is defined as:
$$F(x)=\int_a^x f(t)dt$$
then the sketch will be exactly the same as that of an indefinite integral $G=\int f(x)dx$ with zero integration constant, except shifted downwards by $G(a)$.

 

[Saracen Rue]

How does it sketch the definite integrals? If it sketches the curve of $F(x)$ vs $x$ where $F(x)$ is defined as:
$$F(x)=\int_a^x f(t)dt$$
then the sketch will be exactly the same as that of an indefinite integral $G=\int f(x)dx$ with zero integration constant, except shifted downwards by $G(a)$.

So if I make a equal to a x-intercept of the indefinite integral of f(x), then
$$F(x)=\int_a^x f(t)dt$$
With no shift?

 

[andrewkirk]

Yes, that should work.

 

[Saracen Rue]

Yes, that should work.

Thank you! :)