Making a pH 7 Liquid: A Simple Guide

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SUMMARY

This discussion focuses on the process of creating a pH 7 liquid by mixing an acid and a base. The user proposes a mathematical approach using the equation 8x + 3y = 14 to determine the proportions of acid and base needed. However, the conversation highlights that pH is a logarithmic scale, meaning that a pH 3 solution has significantly more hydrogen ions than a pH 8 solution. Therefore, a simple linear algebraic approach is insufficient; instead, one must consider the hydrogen ion concentrations directly to achieve a neutral pH.

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  • Understanding of pH scale and its logarithmic nature
  • Basic knowledge of acid-base chemistry
  • Familiarity with hydrogen ion concentration calculations
  • Proficiency in algebraic equations
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  • Research the relationship between pH and hydrogen ion concentration
  • Learn about acid-base neutralization reactions
  • Explore the concept of buffer solutions and their role in pH stability
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Chemistry students, educators, and anyone interested in understanding acid-base reactions and pH balance in solutions.

perd1t1on
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Hello. This is probably a really dumb question, but I was wondering how the ph system works in relation to making a ph 7 liquid (which would be water and salt, right?)

The way I was thinking was if you have an acid with a ph3 and a base with a ph8, and you wanted to mix them to produce a ph7 liquid, you would have to do it proportionally:

7*2 = 14 = 8x + 3y = 8(1) + 3(2)
x = 1, y = 2
1 part base, 2 parts acid.

If this is not how it's done, is there a simple way to do it (aka given you have the ph of both the acid and base, what is the ratio to make a ph7 liquid?). This is not a homework question and I'm not a chemist.
 
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As far as I know pH is a logarithmic unit, so a pH of 3 has 105 more H+ ions than a pH of 8. If I'm correct then your simple algebra wouldn't work. It would work if you do it directly with the H+ concentration instead of pH, and also taking in account for the total volume.
 
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