Man Lifts 15kg Bucket from Well: Calculating Depth

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Homework Help Overview

The problem involves calculating the depth of a well from which a man lifts a 15.0 kg bucket, given that he does 3.00 kJ of work and the bucket is lifted at a constant speed.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the definition of work and its relation to the forces acting on the bucket, particularly in the context of constant velocity. There are attempts to apply the formula for work and to clarify the correct force to use in calculations.

Discussion Status

The discussion includes various interpretations of the problem, with some participants offering guidance on the definitions and relationships involved. There is no explicit consensus on the approach to take, but several lines of reasoning are being explored.

Contextual Notes

Participants are considering the implications of constant velocity and the forces acting on the bucket, as well as the specific definition of work in this context.

parwana
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If a man lifts a 15.0 kg bucket from a well and does 3.00 kJ of work, how deep is the well? Assume that the speed of the bucket remains constant as it is lifted.
 
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parwana said:
If a man lifts a 15.0 kg bucket from a well and does 3.00 kJ of work, how deep is the well? Assume that the speed of the bucket remains constant as it is lifted.

What is the definition of work? Look it up, and I'm sure you'll be able to solve this without any difficulties.

Further on, think about why constant velocity is mentioned. What are the forces that are acting on the bucket? In what relation are they (because of constant velocity)?
 
Work= Force times change in x
I got it

I used F= ma to find F

then plugged it in the equation to find x
 
Last edited:
parwana said:
F= ma to find F

Its supposed to be mg where g is ur acceleration of free fall.
 

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