Mapping Real Axis and Im(z)=1 to Tangent Circles?

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SUMMARY

The discussion focuses on finding a Möbius transformation that maps the real axis to the circle defined by |z-1|=1 and the line Im(z)=1 to the circle |z-2|=1. The participants clarify that the circles are tangent at a specific point, correcting an initial misunderstanding regarding their intersection. The transformation is expressed in the standard form z→(az+b)/(cz+d) on the extended complex plane. The conversation highlights the importance of accurately interpreting geometric properties in complex analysis.

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  • Learn how to derive circle equations from complex number representations
  • Explore the concept of tangency in complex analysis
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Homework Statement


Find a Mobius transformation that maps the real axis to the circle |z-1|=1, and the line Im(z)=1 to the circle |z-2|=1

Homework Equations


A mobius transformation is one of the form [tex]z\rightarrow\frac{az+b}{cz+d}[/tex] on the extended complex plane

The Attempt at a Solution



My attempt pretty much comes out to... well, mobius transformations are bijections, but the two lines I'm given in the pre-image only intersect at infinity. So how do I get the two intersection for the circles? I'm thinking maybe I'm really dumb, and they're just tangent, but it looks to me as if they meet at [tex]\frac{3}{2}\pm\frac{\sqrt{3}}{2}i[/tex]
 
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You're right, there does seem to be a problem with the question.
 
I asked someone about it, and it's actually |z|=1 and |z-2|=1, so they're tangent at a point (I was reading off the circle descriptions from the question above previously... whoops).

I was having enough trouble with these stupid things without making them even more difficult for myself.
 

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