Mapping unit circle from one complex plane to another

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The discussion centers on the transformation of the unit circle in the ζ-plane to an ellipse in the z-plane, defined by the relation z = (2/ζ) + ζ. The user seeks assistance in deriving the equation of the ellipse in terms of x and y after expressing z as x + iy. Participants encourage the user to work through the problem by applying known relations and suggest starting with the condition |ζ| = 1. Ultimately, the user successfully derives the ellipse equation as (x/3)² + y² = 1, confirming the mapping from the unit circle to the ellipse. This highlights the importance of engaging with the problem-solving process rather than seeking direct answers.
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I want to show that if the complex variables ζ and z and related via the relation

z = (2/ζ) + ζ

then the unit circle mod(ζ) = 1 in the ζ plane maps to an ellipse in the z-plane.

Then if I write z as x + iy, what is the equation for this ellipse in terms of x and y?

Any help would be much appreciated.

Thanks!
 
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Welcome to PF;
Then if I write z as x + iy, what is the equation for this ellipse in terms of x and y?
... you mean: "how should I go about finding the equation of the ellipse?" Nobody is going to spoon-feed you the actual answer here - but we can help you find it for yourself.

You can help us do that by attempting the problem.

Start out by writing out the relations you know:

1. z = (2/ζ) + ζ
2. |ζ| = 1

3. ζ = γ + iλ
4. z = x + iy

5. ... any other relations that must hold true?

Presumably you can expand 1 and 2 in terms of 3?
Presumably you can look up the general equation of an ellipse?

Now where do you get stuck?
 
I think I've got it now..

Let ζ = u+iv so u²+v²=1 because |ζ| = 1

2/ζ + ζ = 2 / (u+iv) + (u+iv) = 2(u−iv) / (u²+v²) + (u+iv) = 3u−iv

∴ x+iy = 3u−iv and so u=x/3, v=−y

From u²+v² = 1 this yields (x/3)²+y² = 1, an ellipse

Thanks for your help
 
No worries :-)
Sometimes the trick is starting without knowing whe re you are going.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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