Marginal pdf, what am I doing wrong?

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SUMMARY

The discussion focuses on finding the marginal probability density function (pdf) of X, denoted as fX(x), from the joint pdf f(xy) = 49/8 * e^(-3.5y) for the specified ranges. The user initially miscalculated the constant and the bounds for integration, leading to confusion about the limits of integration. The correct approach involves integrating over the region where f(x,y) ≠ 0, specifically from -y to y for y > 0, and recognizing that the marginal pdf is defined as f_X(x) = ∫ f(x,y) dy.

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Rifscape
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Homework Statement



f(xy)=49/8*e^(−3.5*y) 0 < y < inf and −y < x < y

0 otherwise

a. Find the marginal probability density function of X, fX(x). Enter a formula in the first box, and a number for the second and the third box corresponding to the range of x. Use * for multiplication, / for division, ^ for power, abs for absolute value and exp for exponential function. For example, 3abs(x-5)exp(-x/2) means 3|x-5|e-x/2. Use inf for ∞ and -inf for -∞.

I'm not sure what I am doing wrong here, I keep getting 7/4 and the bounds are from -inf to inf right?

Homework Equations


The marginal pdf equation for x.

The Attempt at a Solution



I did the 8/49*∫e^(-3.5*y) from 0 to inf and got 7/4 with the bounds of x being from 0 to inf. What exactly am I doing wrong?

Or would the bounds be from x to infinity? Any advice is appreciated.

Thanks for the help
 
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First of all I think you should check the problem is typed correctly. I don't think what you have given is a density function. Second, draw a picture of the region where ##f(x,y)\ne 0##. You need to know that to know the correct limits for your integrals.
 
LCKurtz said:
First of all I think you should check the problem is typed correctly. I don't think what you have given is a density function. Second, draw a picture of the region where ##f(x,y)\ne 0##. You need to know that to know the correct limits for your integrals.

You're right, it was 49/8 not 8/49 for the constant. I tried drawing the picture, I got that the bounds seem to look like its from -inf to inf. But for the distribution wouldn't I have to get x in terms of y? That's why I thought the bounds would be from -x to x, since x < y and y > -x.
 
Rifscape said:
You're right, it was 49/8 not 8/49 for the constant. I tried drawing the picture, I got that the bounds seem to look like its from -inf to inf. But for the distribution wouldn't I have to get x in terms of y? That's why I thought the bounds would be from -x to x, since x < y and y > -x.
Your original statement of the problem had limits: 0 < y < inf and −y < x < y. That is the region where your ##f(x,y)\ne 0##. Now, the definition of the marginal density is$$
f_X(x) = \int_{-\infty}^\infty f(x,y)~dy$$You only have to integrate over the region where ##f(x,y)\ne 0##. For each ##x## you integrate in the ##y## direction. When ##x<0## where does ##y## go? When ##x>0## where does ##y## go? You need to look at your region. So let's see how you set up that integral.
 
LCKurtz said:
Your original statement of the problem had limits: 0 < y < inf and −y < x < y. That is the region where your ##f(x,y)\ne 0##. Now, the definition of the marginal density is$$
f_X(x) = \int_{-\infty}^\infty f(x,y)~dy$$You only have to integrate over the region where ##f(x,y)\ne 0##. For each ##x## you integrate in the ##y## direction. When ##x<0## where does ##y## go? When ##x>0## where does ##y## go? You need to look at your region. So let's see how you set up that integral.

Would I need to split it up and integrate x from -inf to 0, and then integrate x from 0 to inf?
 
LCKurtz said:
When ##x<0## where does ##y## go? When ##x>0## where does ##y## go? You need to look at your region. So let's see how you set up that integral.

Rifscape said:
Would I need to split it up and integrate x from -inf to 0, and then integrate x from 0 to inf?

You aren't integrating ##x##. It it is a ##y## integral. You could start by answering the two questions I asked you above. It would also help if you would describe the region in words so I know you have the correct region in the first place.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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