- #1

skaterboy1

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## Homework Statement

There are three patchs in which an animal can forage.

Patch 1: Risk of predation is 0. Probability of finding food is 0. Energy value is 0.

Patch 2: Risk of predation is 0.004. Probability of finding food is 0.4 and energy gain is 3.

patch 3: risk of predation is 0.02. Probability of finding food is 0.6 and energy gain is 5.

Foraging in any patch uses one unit of energy reserves. Energy reserves below 4 indicate death. maximum energy capacity for animal is ten units.

Solve this problem for 20 foraging periods to find a patch selection strategy which maximizes the animals probability of survival over this period.

## Homework Equations

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## The Attempt at a Solution

Three patchs; N=3

States: risk, food findings and energy gain.

action: Choosing patchs 1, 2 or 3.

How do I solve this problem?

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