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## Homework Statement

There are three different reactions we did in class.

B-:

_{6}C

^{14}-->

_{7}N

^{14}+ e-

B+:

_{6}C

^{11}-->

_{5}B

_{11}+ e+

Nuclear rxn: alpha particle +

_{7}N

^{14}-->

_{8}O

^{17}+ e+

## Homework Equations

Q tot = (mass inital - mass final) * 931.5 MeV

Charge balance

## The Attempt at a Solution

In class, for B- the teacher wrote down:

Q= (Mass of C nucleus) - (mass of N nucleus) - 1 e-

= (mass of C atom - 6 e-) - (mass of N atom - 7 e-) - (mass of 1 e-)

so -6 -(-7) - 1 = 0 so Q= (mass of C atom) - (mass of N atom)

B+

Q = (mass of C nuc) - (Mass of B nuc) - (mass of e+)

Q= (mass of C atom - 6 e-) - (mass of B atom - 5 e-) - mass of 1 e-

Q= -6 -(-5) -1 = -2, so he said Q total = (mass of C) - (mass of B + 2e-)

Nuclear rxn

Q = (mass of alpha nuc) + (mass of N nuc) - (mass of O nuc) - (mass of e+)

Q = (mass of He - 2 e-) + (mass of N atom - 7 e-) - (mass of O atom - 8 e-) - (mass of e+)

Q = -2 + -7 - (-8) -1 = -2 e-

However, he said in class that the Q = (mass of alpha particle + mass of N atom) - (mass of O atom)

Can someone please clear this up for me? I really don't get the charge/mass balance. Thanks so much