Mass compressing an unattached spring

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SUMMARY

The discussion centers on the dynamics of a mass-spring system where the spring is unattached to a ramp. Key points include the behavior of the spring when compressed, the influence of mass and friction, and the potential for the block to extend beyond the spring's natural length. The analysis indicates that if the spring possesses mass, it will continue to stretch after the block loses contact, influenced by kinetic energy and frictional forces. The complexities of real-world applications necessitate a deeper mathematical understanding of energy transfer and oscillation damping.

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  • Understanding of Hooke's Law and linear force-extension relationships
  • Basic principles of kinetic energy and momentum
  • Knowledge of frictional forces and their effects on motion
  • Familiarity with oscillatory motion and damping in mechanical systems
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How far will the spring extend, given that the block is not attached? Will it extend beyond its natural length? How to calculate at what point the box comes off the spring?
 
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I think it could - extend beyond its unloaded length and, if the spring is not attached to the ramp, slide up the ramp from its original position.
Exactly what happens will depend on the details; the mass of the spring, friction between the spring and the ramp and between the block and the ramp.
Simple questions (or should I say, questions based on a simple model) treat a spring as an ideal store of energy with a well-defined, linear force-extension relation. Once you start modelling taking account of mass and losses, it gets mathematically more difficult.
If the spring has no mass, hence no momentum, it simply returns to its original unloaded length and the block loses contact again at that point. If it has mass then it is obviously moving at that point, so will continue to stretch (the parts of the spring are moving at different speeds) and will also move bodily past that point until gravity stops it.
My intuition is that the block is then at its fastest, as the spring is now slowing down and using its KE to stretch itself. In which case the block may separate at exactly the same point. If there's enough friction, the block may not separate at all - like a critically or over damped oscillation of a spring-mass system.
But I haven't done any maths on it to check any of that.
 
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###/\/\/\/\ <--- ●
wall spring mass

Let t_0 be the time when the spring has compressed the most. If everything is standing still at that moment and the spring is lossless, then flip the direction of the time at t_0 and play the history backwards. The mass bounces back and the spring is left static.

However, the speed of sound cannot be infinite in a spring. Some kinetic energy of the mass is converted to vibration of the spring. Everything is not standing still at the time t_0.

It would be a miracle if the mass would absorb all that vibration by the time it detaches from the spring.

The vibration will cause the spring to bounce from the wall and follow the mass.
 
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