Mass dropped onto vertical spring what is the max compression?

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SUMMARY

The maximum compression of a vertical spring when a mass of 0.5 kg is dropped from a height of 1.5 m onto it, with a spring constant of k = 500 N/m, can be calculated using energy conservation principles. The correct approach involves equating the gravitational potential energy to the elastic potential energy of the spring. The derived formula is mg(h_0 + Δx) = 1/2 k Δx^2, leading to a maximum compression of approximately 0.20 m. The solution provided by the user is confirmed to be correct.

PREREQUISITES
  • Understanding of gravitational potential energy (U = mgh)
  • Familiarity with elastic potential energy (W_sp = 1/2 kx^2)
  • Knowledge of energy conservation principles (W_nc = ΔK + ΔU)
  • Basic algebra for solving equations
NEXT STEPS
  • Study the principles of energy conservation in mechanical systems
  • Learn about Hooke's Law and its applications in spring mechanics
  • Explore the concept of maximum compression in spring-mass systems
  • Practice solving similar problems involving springs and gravitational forces
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Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators looking for examples of spring dynamics in real-world applications.

MathHelpa
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Homework Statement


A mass m = 0.5 kg is dropped from a height of 1.5m above the end of an uncompressed vertical spring with k = 500 N/m. What is the maximum compression of the spring?


Homework Equations


f_sp = -kx
W_sp = 1/2 kx^2
W_nc = ΔK + ΔU
K = 1/2 mv^2
U = mgh
W = Fdcos∅
p = mv


The Attempt at a Solution


My friend and me were in different groups and they did the problem differently and came to a different answer. We set up ours as mg(h_0 + Δx) = 1/2hΔx^2 and came to a answer of .18 and rounded to .20 for Δx. My friend got much higher number so I was wondering what the answer really was and how to do it correctly if we are wrong.
 
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What are 'h' and 'h_0' in you formula?
 
MathHelpa said:

Homework Statement


A mass m = 0.5 kg is dropped from a height of 1.5m above the end of an uncompressed vertical spring with k = 500 N/m. What is the maximum compression of the spring?


Homework Equations


f_sp = -kx
W_sp = 1/2 kx^2
W_nc = ΔK + ΔU
K = 1/2 mv^2
U = mgh
W = Fdcos∅
p = mv


The Attempt at a Solution


My friend and me were in different groups and they did the problem differently and came to a different answer. We set up ours as mg(h_0 + Δx) = 1/2hΔx^2

You meant 1/2 kdx^2...


MathHelpa said:
and came to a answer of .18 and rounded to .20 for Δx. My friend got much higher number so I was wondering what the answer really was and how to do it correctly if we are wrong.

Your solution is correct.

ehild
 

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