Mass hanging from more than two strings

  • Thread starter Thread starter dimitri151
  • Start date Start date
  • Tags Tags
    Mass Strings
AI Thread Summary
The discussion centers on solving for the tensions in a mass suspended from three strings in a plane, exploring whether the problem is solvable or indeterminate. It is noted that typically, two strings will be taut while one remains slack, leading to potential indeterminacy if the string lengths are precisely calibrated. The conversation shifts to the concept of using springs instead of strings, where the force constant allows for a solvable scenario. It is emphasized that real strings behave like springs due to their inherent flexibility, which can influence the problem's determinacy. Ultimately, the setup can be analyzed using Hooke's Law to determine the mass's equilibrium position.
dimitri151
Messages
117
Reaction score
3
Is there a way to solve for the tensions in a mass hanging from three strings all in a plane, say? Is it solvable or is it indeterminate?
 
Physics news on Phys.org
dimitri151 said:
Is there a way to solve for the tensions in a mass hanging from three strings all in a plane, say? Is it solvable or is it indeterminate?

Three strings, all in one plane... So, for instance, you would scribe a straight line on the ceiling, put three hooks on points on this line, take three strings, tie one to each hook, tie the all three free ends to a single mass and let the mass hang, eventually settling into an equilibrium position?

In the usual case, two strings will be taut and the third will be slack.

If the string lengths work out just right the result will be on a cusp between a solution where one string is slack and another solution where a different string is slack. In that case, the result will be indeterminate.
 
It is statically indeterminate. If you assume a force constant k, with F=k\Delta x, for each string, it can be solved.
 
Yes, jbriggs, that's exactly the setup. (I should have said it that way in the first place.)
Thanks, Meir. By force constant , you mean if you hang the mass from springs instead of strings, then it is solvable?
 
dimitri151 said:
By force constant , you mean if you hang the mass from springs instead of strings, then it is solvable?

Yes. Remember that in the real world, inextensible strings do not exist. Real strings always behave like "springs."

Sometimes, the fact that all the strings have the same flexibility (e.g. they are all made of the same material) is enough information to change an indeterminate problem to a determinate one, and the exact value of the stiffness is not important.
 
If you could just give a nod if my setup is done correctly.
If you hang a mass from one spring, the length of the spring with no force is L, the mass is m, the spring constant is k then you just apply Hooks Law so the mass will hang L+mg/k from the ceiling (since F=-kx)?
 
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
I passed a motorcycle on the highway going the opposite direction. I know I was doing 125/km/h. I estimated that the frequency of his motor dropped by an entire octave, so that's a doubling of the wavelength. My intuition is telling me that's extremely unlikely. I can't actually calculate how fast he was going with just that information, can I? It seems to me, I have to know the absolute frequency of one of those tones, either shifted up or down or unshifted, yes? I tried to mimic the...
Back
Top