Mass of a Pendulum on a Grandfather Clock

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SUMMARY

The discussion centers on calculating the mass of a pendulum in a grandfather clock, which swings at a 15° angle and completes one revolution every 2.0 seconds. The maximum tension in the chain is given as 2.0N, and the length of the chain is 1.0 meter. The user initially attempted to use the equation F=mg but was corrected to apply the centripetal force formula Fc = mv²/r for the calculation. The user ultimately derived the velocity as 0.842 m/s and seeks further guidance on determining the mass using the correct formulas.

PREREQUISITES
  • Understanding of centripetal force and its formula (Fc = mv²/r)
  • Knowledge of free body diagrams (FBD) and their application in physics
  • Familiarity with basic kinematics, including velocity calculations
  • Concept of conservation of energy in mechanical systems
NEXT STEPS
  • Study the derivation and application of the centripetal force formula (Fc = mv²/r)
  • Learn how to construct and analyze free body diagrams for dynamic systems
  • Explore kinematic equations and their use in circular motion
  • Investigate the principles of conservation of energy in pendulum motion
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Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for practical examples of pendulum dynamics.

twenty5
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Homework Statement


Can someone please revise my work? It's quite short )

Question:
A grandfather clock is designed to have a pendulum which swings a mass at the end of a chain in a horizontal circular motion. The pendulum is designed to swing at 15° off the vertical and to complete one revolution every 2.0 seconds. The chain is 1.0 metre long and the maximum tension in the chain is 2.0N

Length of string : 1m
angle at the top: 15°
1 Revolution = 2s
FT : 2.0N


Homework Equations


F=mg


The Attempt at a Solution


I drew the FBD, which then I got:

2.0cos15° = FT(y) = m (9.81)
did the algebra... and ended up with

m = 0.1969kg


I have a positive feeling that this is too little. Any thoughts? thanks! I'll be here all day haha
 
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hi twenty5! :smile:
twenty5 said:
I drew the FBD, which then I got:

2.0cos15° = FT(y) = m (9.81)

no, you've tried to use ∑F = 0 in the vertical direction …

but there's a vertical acceleration, so you can't :redface:

in fact, there's no obvious direction in which the acceleration is zero …

you'll have to use ∑F = ma and https://www.physicsforums.com/library.php?do=view_item&itemid=27":wink:
 
Last edited by a moderator:
m k thanks I'll see what I can come up with then I'll post my results thakns!
 
deleted ~ found out this method was wrong. pleaswe look at my next post
 
Last edited:
ok so what I am at now is:

Fc = mv2 / rI got Velocity by getting the radius, and then getting the circumference from that. Circumference = 1.684m
We know that it takes 2 seconds for 1 revolution. So I used V = d/t V = 1.684 / 2 V = 0.842m/s
Now I'm left withFc = m (0.842 )2 / 0.268can I get some sort of push as to which way I should head now?

I'm looking for the mass. But the only formulae I know of that gives Force of centripetl is that one that I listed...
 
hi twenty5! :smile:
twenty5 said:
… So I used V = d/t

no, that only works for constant speed

try using conservation of energy :wink:
 
ah. okay thank you very much sir.
 

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