Mass of a Pendulum on a Grandfather Clock

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Homework Help Overview

The problem involves a grandfather clock's pendulum, which swings a mass in a horizontal circular motion at a 15° angle from the vertical, completing one revolution every 2.0 seconds. The length of the chain is 1.0 meter, and the maximum tension in the chain is given as 2.0N.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of free body diagrams (FBD) and the application of forces in vertical and horizontal directions. There is a question about the appropriateness of using static equilibrium equations given the presence of vertical acceleration. Some participants suggest using centripetal force equations and conservation of energy as alternative approaches.

Discussion Status

The discussion is ongoing, with participants exploring different methods to find the mass of the pendulum. Some guidance has been offered regarding the need to reconsider the application of certain equations due to the dynamics of the motion involved.

Contextual Notes

There is a mention of a deleted post indicating a realization of an incorrect method previously attempted. Participants are navigating through various interpretations of the problem setup and the relevant physics principles.

twenty5
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Homework Statement


Can someone please revise my work? It's quite short )

Question:
A grandfather clock is designed to have a pendulum which swings a mass at the end of a chain in a horizontal circular motion. The pendulum is designed to swing at 15° off the vertical and to complete one revolution every 2.0 seconds. The chain is 1.0 metre long and the maximum tension in the chain is 2.0N

Length of string : 1m
angle at the top: 15°
1 Revolution = 2s
FT : 2.0N


Homework Equations


F=mg


The Attempt at a Solution


I drew the FBD, which then I got:

2.0cos15° = FT(y) = m (9.81)
did the algebra... and ended up with

m = 0.1969kg


I have a positive feeling that this is too little. Any thoughts? thanks! I'll be here all day haha
 
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hi twenty5! :smile:
twenty5 said:
I drew the FBD, which then I got:

2.0cos15° = FT(y) = m (9.81)

no, you've tried to use ∑F = 0 in the vertical direction …

but there's a vertical acceleration, so you can't :redface:

in fact, there's no obvious direction in which the acceleration is zero …

you'll have to use ∑F = ma and https://www.physicsforums.com/library.php?do=view_item&itemid=27":wink:
 
Last edited by a moderator:
m k thanks I'll see what I can come up with then I'll post my results thakns!
 
deleted ~ found out this method was wrong. pleaswe look at my next post
 
Last edited:
ok so what I am at now is:

Fc = mv2 / rI got Velocity by getting the radius, and then getting the circumference from that. Circumference = 1.684m
We know that it takes 2 seconds for 1 revolution. So I used V = d/t V = 1.684 / 2 V = 0.842m/s
Now I'm left withFc = m (0.842 )2 / 0.268can I get some sort of push as to which way I should head now?

I'm looking for the mass. But the only formulae I know of that gives Force of centripetl is that one that I listed...
 
hi twenty5! :smile:
twenty5 said:
… So I used V = d/t

no, that only works for constant speed

try using conservation of energy :wink:
 
ah. okay thank you very much sir.
 

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