Mass of a planet using a pendulum

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SUMMARY

The discussion focuses on calculating the mass and radius of a planet using a pendulum's period at two different heights. The explorer uses the equations of motion for a pendulum, specifically T = 2π√(L/g) and g = GM/r², to derive the formulas for mass (M) and radius (r). The derived mass formula is M = 8000π²L / G(T2² - T1²). However, the calculated radius appears to be significantly smaller than expected, indicating a potential error in the calculations or assumptions made regarding the radius adjustment when climbing 2 km.

PREREQUISITES
  • Understanding of gravitational force equations (g = GM/r²)
  • Familiarity with pendulum motion and period calculation (T = 2π√(L/g))
  • Basic algebra for manipulating equations and solving for variables
  • Knowledge of units and conversions, particularly in gravitational contexts
NEXT STEPS
  • Review the derivation of gravitational equations, particularly the relationship between mass and radius
  • Explore the impact of altitude on gravitational acceleration and pendulum period
  • Investigate potential errors in assumptions regarding the pendulum's length and the effects of altitude
  • Learn about the implications of using approximations in gravitational calculations
USEFUL FOR

Students in physics or engineering, educators teaching gravitational concepts, and anyone interested in practical applications of pendulum mechanics for planetary measurements.

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Homework Statement


An explorer wants to find the mass and radius of a planet he has landed on. He uses a pendulum he has with him and observes it takes a period of T1 to complete. He then climbs 2km up and observes period t2. Find planetary Radius r and Mass m

Homework Equations


g = GM/r^2

T = 2pi(sqrt(L/g)



The Attempt at a Solution



g= 4pi^2L/T1^2 = Gm/r^2 #1

-----
4pi^2L/T2^2= Gm/(r^2 + 2000)#2

I took #1 and solved for r,

r=sqrt((GMT1^2)/4pi^2L)


input that in two and came up with

GmT1^2 + L8000pi^2= GmT2^2

after canceling

M=8000pi^2L/G(t2^2-T1^2)

when i evaluate this I get a reasonable mass, 5.~ *10^15 but my radius is way to small



any thoughts?
 
Physics news on Phys.org
(r^2 + 2000) is not the same as (r+2000)^2
 
mgb_phys said:
(r^2 + 2000) is not the same as (r+2000)^2

ya sorry type o there,
 

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