What is the Mass of Air in a Cylindrical Column as a Function of Height?

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SUMMARY

The mass of air in a cylindrical column as a function of height is determined by integrating the density function ρ = ρ0e−z/H, where ρ0 = 1.3 kg/m³ and H = 10 km. The integration is performed from 0 to z, leading to the formula m = ∫[0,z] πr²e−z/Hρ0 dz. To solve this integral, substitution for the argument of the exponential is required. The discussion emphasizes the importance of proper notation in integration, although it acknowledges that minor notation errors do not typically affect the outcome.

PREREQUISITES
  • Understanding of calculus, specifically integration techniques
  • Familiarity with exponential functions and their properties
  • Knowledge of the formula for the volume of a cylinder
  • Basic concepts of atmospheric physics, particularly air density variations
NEXT STEPS
  • Study integration by substitution techniques in calculus
  • Explore the derivation of the exponential decay function in atmospheric science
  • Learn how to calculate the mass of varying density fluids in cylindrical coordinates
  • Investigate the implications of air density changes on meteorological models
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Students in physics or engineering, particularly those studying fluid dynamics and atmospheric science, as well as educators looking for practical examples of integration in real-world applications.

~Sam~
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Homework Statement


The density of air in the lower atmosphere decreases exponentially with height: ρ = ρ0e−z/H
where ρ0 = 1.3 kg/m3 and H = 10 km. What is the mass of air in a cylindrical column of cross-sectional area 1 m2 and height z, as a function of z? How much mass is contained in such a column 1.0 km high?



Homework Equations



Volume of a Cylinder= pi*r*h


The Attempt at a Solution



I think I need to integrate from 0 to z to get the formula for mass. However, I'm not sure what the equation is that I need to integrate. I was thinking it might be something like intg[0,z] pi*r2e-z/Hρ0dz. Still if it that was, I see an issue with integrating e-z/H. I haven't gone to the second part because I need to know the first.
 
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Looks good to me.

m=\int^{z}_{0}dm=\int^{z}_{0}\pi r^{2}e^{-z/H}\rho_{0}dz

of course a mathematician will tell you that integrating for 0 to z is bad notation but its unlikely to give you the wrong answer.
 
How would you integrate e-z/h?
 
By substitution for the argument of the exponential.
 
Phyisab**** said:
By substitution for the argument of the exponential.

I'm not quite sure what you mean. Do you integration by substitution? Could you elaborate or give an example?
 
Yes integration by substitution. Its a pretty elementary integration, look in a calculus book. Sorry I don't have time right now to explain.
 

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