Mass on a Spring: Determine Periodic Time, Frequency & Acceleration

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Homework Help Overview

The discussion revolves around a physics problem involving a mass on a spring, specifically focusing on determining the periodic time, frequency, and acceleration of the system. The spring has a stiffness of 30 KN/m and supports an 8 kg mass that is displaced by 10 mm, leading to linear oscillations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the equations related to maximum velocity and acceleration, questioning their dependence on time. There is an exploration of whether the problem statement is correctly written and how to interpret the terms "maximum" in the context of velocity and acceleration.

Discussion Status

Participants are actively engaging with the problem, with some offering alternative equations for maximum velocity and acceleration. There is a recognition of confusion regarding the original equations presented and the validity of the problem statement itself. Multiple interpretations of the problem are being explored.

Contextual Notes

There are indications that previous problems in the assignment may have had unclear wording, leading to uncertainty about how to approach this particular question. Participants are considering whether to treat velocity and acceleration without the "maximum" qualifier.

Thermoman
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Homework Statement


A spring has a stiffness of 30 KN/m and supports a mass of 8 kg. The mass is pulled so that the spring t extends by amplitude of 10 mm and its released so that it produces linear oscillations .

Homework Equations


(i) Determine the periodic time,circular frequency,and the natural frequency f.
(ii) Calculate the maximum velocity of the mass.(iii) Calculate the maximum acceleration of the mass.

The Attempt at a Solution


Periodic time;

T = 1/f = (1 / 9.75) = 0.10260s

Circular frequency;

W= √ k / M w = √ 30000 / 8 = 61.24 rad/s

Natural frequency;

F = w / 2 π = 61.24 / (2π) = 9.75Hz

Displacenent . [/B]10 cos X (61.24 X 0.10260) = - 5.27 mm
Which equations do I use ? Velocity = ωx sin ωt Or max velocity = x cos ωt =0
Acceleration= ω^2 x sin ωt Or max acceleration= x cos ωt

If I am correct with displacement , it does not equal zero.Which is throwing me !
 
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i don't think those equations of max velpcity have any sense. if they are maximum, why would tgey depend on time??
 
The question is written out word for word. There have been other problems with questions on this assignment and the one on thermodynamics before it ! Its an online BTEC. Are you saying the question it self is incorrectly written (others have been). And i struggled with them too.
Should i just treat it as velocity ? And acceleration , Leaving Max out of it ?
 
look, max velocity is $\omega xmax$. max acceleration is $\omega^2 xmax$. you shouldn't have any "time" involved.
 
Those are the equations used in the course examples ? So you're saying the equations I put up are incorrect to find max acc and max Vel ?
 
Thermoman said:
Those are the equations used in the course examples ? So you're saying the equations I put up are incorrect to find max acc and max Vel ?
yes, those equations are wrong. the correct equations are those that I gave you. it is easy to do it yourself, just derive with respect to time and rember that sine and cosine are between 1 and -1. it is crucial to understand this that the maximum velocity or acceleration can't involve time
 
Thank you melthengylf...No wonder I am bamboozed
 

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