Mass on a Spring: Determine Periodic Time, Frequency & Acceleration

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SUMMARY

The discussion focuses on calculating the periodic time, circular frequency, natural frequency, maximum velocity, and maximum acceleration of a mass-spring system with a stiffness of 30 kN/m and a mass of 8 kg. The periodic time (T) is determined to be 0.10260 seconds, the circular frequency (ω) is calculated as 61.24 rad/s, and the natural frequency (f) is found to be 9.75 Hz. The maximum velocity and maximum acceleration equations are clarified, emphasizing that they should not involve time, as the correct formulas are max velocity = ωx and max acceleration = ω²x, where x is the amplitude.

PREREQUISITES
  • Understanding of harmonic motion principles
  • Knowledge of spring constant and mass relationship
  • Familiarity with angular frequency and natural frequency calculations
  • Ability to differentiate trigonometric functions in the context of oscillations
NEXT STEPS
  • Study the derivation of equations for maximum velocity and maximum acceleration in harmonic motion
  • Explore the relationship between spring constant and mass in oscillatory systems
  • Learn about energy conservation in mass-spring systems
  • Investigate the effects of damping on oscillations in springs
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Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators looking to clarify concepts related to mass-spring systems.

Thermoman
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Homework Statement


A spring has a stiffness of 30 KN/m and supports a mass of 8 kg. The mass is pulled so that the spring t extends by amplitude of 10 mm and its released so that it produces linear oscillations .

Homework Equations


(i) Determine the periodic time,circular frequency,and the natural frequency f.
(ii) Calculate the maximum velocity of the mass.(iii) Calculate the maximum acceleration of the mass.

The Attempt at a Solution


Periodic time;

T = 1/f = (1 / 9.75) = 0.10260s

Circular frequency;

W= √ k / M w = √ 30000 / 8 = 61.24 rad/s

Natural frequency;

F = w / 2 π = 61.24 / (2π) = 9.75Hz

Displacenent . [/B]10 cos X (61.24 X 0.10260) = - 5.27 mm
Which equations do I use ? Velocity = ωx sin ωt Or max velocity = x cos ωt =0
Acceleration= ω^2 x sin ωt Or max acceleration= x cos ωt

If I am correct with displacement , it does not equal zero.Which is throwing me !
 
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i don't think those equations of max velpcity have any sense. if they are maximum, why would tgey depend on time??
 
The question is written out word for word. There have been other problems with questions on this assignment and the one on thermodynamics before it ! Its an online BTEC. Are you saying the question it self is incorrectly written (others have been). And i struggled with them too.
Should i just treat it as velocity ? And acceleration , Leaving Max out of it ?
 
look, max velocity is $\omega xmax$. max acceleration is $\omega^2 xmax$. you shouldn't have any "time" involved.
 
Those are the equations used in the course examples ? So you're saying the equations I put up are incorrect to find max acc and max Vel ?
 
Thermoman said:
Those are the equations used in the course examples ? So you're saying the equations I put up are incorrect to find max acc and max Vel ?
yes, those equations are wrong. the correct equations are those that I gave you. it is easy to do it yourself, just derive with respect to time and rember that sine and cosine are between 1 and -1. it is crucial to understand this that the maximum velocity or acceleration can't involve time
 
Thank you melthengylf...No wonder I am bamboozed
 

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