Mastering Coulomb's Law: Troubleshooting Sign and Distance Issues

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Homework Help Overview

The discussion revolves around applying Coulomb's Law to determine the position where the net force on a unit positive charge is zero due to two other charges. Participants are exploring the implications of signs and distances in the context of electrostatic forces.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of the problem, including the distances from the charges and the signs of the forces involved. There is an attempt to equate the forces acting on a unit positive charge to find a specific distance.

Discussion Status

The discussion includes various interpretations of the problem setup, with some participants providing guidance on how to approach the force equations. There is an acknowledgment of confusion regarding the initial setup and the calculations involved.

Contextual Notes

Participants are navigating issues related to the signs of the charges and the distances involved in the calculations. There is a mention of the forces needing to be equal and opposite, and the original poster expresses uncertainty about their understanding of the problem.

luap12
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1. Homework Statement [http://img44.imageshack.us/img44/1104/58339946.jpg ][/URL]



2. Homework Equations [F=k*abs(q1)*abs(q2)/r^2]



3. I understand the equation, but I am having trouble with my signs and also how to include the distance in the equation. I know that the force can't be zero between the charges, and I think it has to be farthest away from the larger positive charge to make them equal to zero. The forces point in the same direction because they are opposite.]
 
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Consider a point at a distance x from -q toward right, and find the forces on a unit positive charge due to two charges. Equate them to get the value of x.
 
I don't understand what you mean by that... I think I'm over-thinking this.
 
Force on unit positive charge due to -q at a distance x*1o^-2 m from it is...?
Force on unit positive charge due to 2q at a distance (10 + x)*10^-2 m is...?
Since net force is zero, equate them to find x.
 
Thanks very much, I got it now.

((k*q)/x^2)-((k*2q)/(x+10)^2)=0, solving for x gives 24.142cm. Accounting for the distance of 5cm on the x-axis give the point to be 29.142cm. This was the correct answer. Thanks!
 

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