Mastering Square Roots: Simplifying Division, Addition, and Subtraction

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Homework Help Overview

The discussion revolves around simplifying square roots in the context of division, addition, and subtraction. Participants are exploring rules and methods for handling expressions involving square roots, specifically focusing on simplification techniques.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to simplify expressions such as 5√24 ÷ 2√18, √40 + √90, and √50 - √18. Questions are raised about the rules for simplifying square roots and how to handle coefficients when extracting roots.

Discussion Status

Some participants have provided hints about simplifying square roots and rationalizing fractions. There is an ongoing exploration of different methods to combine and simplify square roots, with no explicit consensus reached on a single approach.

Contextual Notes

Participants express uncertainty about notation and the simplification process, indicating a need for clarification on the rules governing square roots and their operations. There is mention of the challenge in adding and subtracting surds compared to multiplication and division.

w3tw1lly
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I feel embarassed to ask these questions but what is the rule for to simplify division, addition, and subtraction square roots? Here are some questions:

SIMPLIFY:[tex]5\sqrt{24}\div2\sqrt{18}[/tex]
[tex]\sqrt{40} + \sqrt{90}[/tex]

[tex]\sqrt{50} - \sqrt{18}[/tex]
 
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What have you tried? You need to simplify the square roots. For example, write the first question as [tex]\frac{5\sqrt{24}}{2\sqrt{18}}[/tex] Now, can you simplify [itex]\sqrt{24}[/itex] and [itex]\sqrt{18}[/itex]?

[Hint: write each number under the sqrt sign as a product of primes.]
 
cristo said:
What have you tried? You need to simplify the square roots. For example, write the first question as [tex]\frac{5\sqrt{24}}{2\sqrt{18}}[/tex] Now, can you simplify [itex]\sqrt{24}[/itex] and [itex]\sqrt{18}[/itex]?

[Hint: write each number under the sqrt sign as a product of primes.]
Sorry, I meant to write the question like a fraction I just didn't know the code. When you are simplifying roots, and you take out let's say the root of 4, do you times the number already outside the root sign by 2?

[tex]\frac{5\sqrt{24}}{2\sqrt{18}}[/tex]
=[tex]\frac{5\sqrt{4*6}}{2\sqrt{3*6}}[/tex] (don't know what to do, so long since we had done radicals)
 
Last edited:
"When you are simplifying roots, and you take out let's say the root of 4, do you times the number already outside the root sign by 2?"

Yes.
 
Also, remember to rationalize the fraction^^
 
w3tw1lly said:
Sorry, I meant to write the question like a fraction I just didn't know the code. When you are simplifying roots, and you take out let's say the root of 4, do you times the number already outside the root sign by 2?

[tex]\frac{5\sqrt{24}}{2\sqrt{18}}[/tex]
=[tex]\frac{5\sqrt{4*6}}{2\sqrt{3*6}}[/tex] (don't know what to do, so long since we had done radicals)

[tex]\frac{5\sqrt{4*6}}{2\sqrt{3*6}}=\frac{5\cdot 2\cdot\sqrt{6}}{2\cdot\sqrt{3}\cdot\sqrt{6}}[/tex]

Can you simplify this?
 
w3tw1lly said:
I feel embarassed to ask these questions but what is the rule for to simplify division, addition, and subtraction square roots? Here are some questions:







[tex]\sqrt{40} + \sqrt{90}[/tex]




[tex]\sqrt{50} - \sqrt{18}[/tex]


[tex]\sqrt{40} + \sqrt{90}[/tex]=[tex]\sqrt{4*10}+\sqrt{9*10}[/tex]=2[tex]\sqrt{10}+3\sqrt{10}[/tex]=

can you go from here??
 
this may confuse you more but when you add fractions you need to get the denominator (number on the bottom of fraction) the same. The same goes with surds (square roots), you need to get the number inside the root the same on each surd in oder to add/subtract.


I find it harder to do the + - surds than the x and / surds

When you divide:
[tex]\sqrt{a} \div \sqrt{b} = \frac {\sqrt{a}}{\sqrt{b}}[/tex] which is also written as [tex]\sqrt{\frac{a}{b}}[/tex]

Have a look

http://www.mathsrevision.net/gcse/pages.php?page=6

and

http://www.bbc.co.uk/schools/gcsebitesize/maths/numberih/surdshrev2.shtml
 
Last edited by a moderator:

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