Mastering the Chain Rule: A Quick Guide for Calculus Students

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To find dy/dx for the function y = 2x / (1+x^2)^2, both the chain rule and the quotient rule are necessary due to the nested functions involved. While the quotient rule is a straightforward approach, rewriting the function as y = 2x(1+x^2)^-2 allows for the application of the product rule instead. Some participants suggest that using only the chain rule might be possible, but ultimately, both rules are needed for a complete solution. The discussion emphasizes the importance of understanding the relationship between these calculus concepts. Mastering these techniques is essential for effectively solving similar problems in calculus.
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Homework Statement


y = 2x / (1+x^2)^2

Find dy/dx

Homework Equations


Chain rule


The Attempt at a Solution


I completely forgot how to apply the chain rule.. I mean, I can always apply the quotient rule, but I'm sure this is 1000 times easier if you can apply the chain rule. Do you do something like

u = 1+x^2
du = 2x

so

y = du/u

But I may be getting confused with substitution rule with integration.. it's been a while since I touched calculus.. any suggestions?
 
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Chain rule goes something like
dy/dx=dy/du*du/dv*...*df/dx .

It is usually used when you when you have a nested combination of functions, ie functions within functions.

For your question, you need to use both the quotient rule as well as the chain rule ( (1+x^2)^2, which is the funtion 1+x^2 within a squaring function ) .

Can you finish your problem now ?
 
arunbg said:
Chain rule goes something like
dy/dx=dy/du*du/dv*...*df/dx .

It is usually used when you when you have a nested combination of functions, ie functions within functions.

For your question, you need to use both the quotient rule as well as the chain rule ( (1+x^2)^2, which is the funtion 1+x^2 within a squaring function ) .

Can you finish your problem now ?

Right.. that's the BRUTE force way to do it.

I was wondering if there was a way to finish this without even applying the quotient rule
 
if you don't want to use the quotient rule you can bring the denominator up top so:y= 2x (1+x^2)^{-2} now use the product rule
 
l46kok said:
Right.. that's the BRUTE force way to do it.

I was wondering if there was a way to finish this without even applying the quotient rule

Yes, just write the expression as 2x(1+x2)-2, and use the product rule on this.
 
suspenc3 said:
if you don't want to use the quotient rule you can bring the denominator up top so:y= 2x (1+x^2)^{-2} now use the product rule

I guess that's true, but when I saw the relating terms, I was thinking this could be solved by ONLY using chain rule.

I guess it's impossible.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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