Mastering Trig Substitution for Evaluating Integrals of 1/x(4x+1)^1/2 in Calc II

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GravityGirl
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evaluate the integral of 1/x(4x+1)^1/2

so what i am thinking is that i will have to use a trig substution some how for
4x+1

maybe x=secu since the substution for a^2+x^2=sec^2u

but i am not sure how to go ahead and do it

please help me
 
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GravityGirl said:
evaluate the integral of 1/x(4x+1)^1/2

so what i am thinking is that i will have to use a trig substution some how for
4x+1

maybe x=secu since the substution for a^2+x^2=sec^2u

but i am not sure how to go ahead and do it

please help me
Well, as Dick pointed out, you should let [tex]u = \sqrt{4x + 1}[/tex]
Or, in general, if you meet some radical, then it's common to let u = that whole radical, and then go from there.

You only let x = sec(u), when you meet: [tex]\sqrt{x ^ 2 - 1}[/tex], or when encountering [tex]\sqrt{x ^ 2 - a ^ 2}[/tex], you then let x = a sec(u).

Can you go from here? :)
 
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