I've long understood that voltage is stepped-up in power t-lines to decrease losses, however, I've never really understood the math reasoning behind it.(adsbygoogle = window.adsbygoogle || []).push({});

Isn't P = V^2/R the same as P = I^2*R? If so, it seems that either increasing V or increasing I would invoke the same losses... Could someone explain?

Thanks

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# Math for why voltage is stepped-up in power lines?

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