MHB Math Help: Understand How to Compute $F_{X_1}(x)$

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The discussion centers on understanding the computation of the cumulative distribution function \( F_{X_1}(x) \) using the binomial distribution. The formula \( F_{X_1}(x) = \sum_{j=1}^n \binom{n}{1} F^1(x) (1-F(x))^{n-1} \) represents the probability of obtaining at least one success in \( n \) trials. It is derived from the complement rule, where \( F_{X_1}(x) \) is calculated as \( 1 - (1 - F(x))^n \). This indicates that the total probability for a specific value \( x \) sums to 1, confirming that \( F_{X_0}(x) = 1 \). The explanation emphasizes the relationship between the binomial distribution and cumulative probabilities.
WMDhamnekar
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Now, I don't understand how did author compute $F_{X_1}(x) = \displaystyle\sum_{j=1}^n \binom{n}{1} F^1(x) (1-F(x))^{n-1} = 1-(1-F(x))^n ?$ (I know L.H.S = R.H.S)

Would any member of Math help board explain me that? Any math help will be accepted.
 
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The formula $\binom nj F^j(x)(1-F(x))^{n-j}$ is the probability mass function of the binomial distribution with parameters $p=F(x)$ and $n$.
Consequently we have that all possibilities for a specific $x$ sum up to $1$.
It implies that $F_{X_0}(x)=1$.
We can use the complement rule $P(A^c)=1-P(A)$ to calculate $F_{X_1}(x)$.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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