Math Help: Understand How to Compute $F_{X_1}(x)$

Click For Summary
SUMMARY

The computation of $F_{X_1}(x)$ is derived from the binomial distribution's probability mass function, expressed as $F_{X_1}(x) = \displaystyle\sum_{j=1}^n \binom{n}{j} F^j(x) (1-F(x))^{n-j}$. This formula simplifies to $F_{X_1}(x) = 1 - (1 - F(x))^n$, confirming that the left-hand side equals the right-hand side. The complement rule, $P(A^c) = 1 - P(A)$, is utilized to establish the relationship between $F_{X_1}(x)$ and the cumulative distribution function.

PREREQUISITES
  • Understanding of binomial distribution and its probability mass function
  • Familiarity with cumulative distribution functions (CDF)
  • Knowledge of the complement rule in probability
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of the binomial distribution in detail
  • Learn about cumulative distribution functions and their applications
  • Explore the complement rule in probability theory
  • Practice problems involving the computation of probabilities using binomial distributions
USEFUL FOR

Students studying probability and statistics, educators teaching mathematical concepts, and anyone seeking to deepen their understanding of binomial distributions and cumulative distribution functions.

WMDhamnekar
MHB
Messages
378
Reaction score
30
1655630667801.png


Now, I don't understand how did author compute $F_{X_1}(x) = \displaystyle\sum_{j=1}^n \binom{n}{1} F^1(x) (1-F(x))^{n-1} = 1-(1-F(x))^n ?$ (I know L.H.S = R.H.S)

Would any member of Math help board explain me that? Any math help will be accepted.
 
Physics news on Phys.org
The formula $\binom nj F^j(x)(1-F(x))^{n-j}$ is the probability mass function of the binomial distribution with parameters $p=F(x)$ and $n$.
Consequently we have that all possibilities for a specific $x$ sum up to $1$.
It implies that $F_{X_0}(x)=1$.
We can use the complement rule $P(A^c)=1-P(A)$ to calculate $F_{X_1}(x)$.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
1K
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K