carameled
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Prove by math induction that
n
sigma 3i + 1 = n/2 (3n + 5)
i = n
n
sigma 3i + 1 = n/2 (3n + 5)
i = n
The discussion revolves around proving a mathematical statement using induction, specifically involving sigma notation. Participants are exploring the validity of the induction hypothesis and the base case for the summation formula.
Participants do not appear to reach a consensus on the understanding of the induction process, with some expressing confusion and others attempting to clarify the concepts involved. The discussion remains unresolved regarding the validity of the statement for the base case.
There are indications of missing foundational knowledge about mathematical induction among some participants, which may affect their ability to engage with the problem effectively.
MarkFL said:I think what you mean is the induction hypothesis \(P_n\):
$$\sum_{i=1}^{n}\left(3i+1\right)=\frac{n}{2}(3n+5)$$
The first thing we want to do is confirm the base case \(P_1\) is true:
$$\sum_{i=1}^{1}\left(3i+1\right)=\frac{1}{2}(3(1)+5)$$
Is this true?
carameled said:Wow, well I'm just asking for the prove with math induction. I don't understand any of that..
MarkFL said:You don't understand what an induction hypothesis is, or demonstrating the truth of the base case? These are fundamental to induction. What method have you been taught?