- #1
ksm2288
- 5
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Homework Statement
http://img152.imageshack.us/img152/8286/imag0103l.jpg
*I'm aware my free body diagram is off and that normal force should be in the left quadrant.
Homework Equations
F=m*a
The Attempt at a Solution
Would I be correct in saying..
Fg of A = mg * sin (20)
= 2kg * 9.8 * sin (20)
=17.9N
Fg of B= mg
= (3 kg) (9.8 m/s^2)
=29.4N
Fnet = 29.4N - 17.9N = 11.5 N (tension of massless rope)
F= m*a
a= F/m
a of (A) = 11.5/2 = 5.75 m/s^2
a of (B) = 11.5/3 = 3.83 m/s^2
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