Mathematical proof for non linear system

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SUMMARY

The discussion centers on proving that a continuous-time processing system with two inputs and one output is nonlinear. The linear sub-system H is defined by the impulse response h(t) = e^(-2t). Participants analyze the condition for linear stability, represented by the equation α1y1(t) + α2y2(t) = H {α1x1(t) + α2x2(t)}. Despite initial calculations suggesting linearity, the consensus is that the input to H must be reconsidered, particularly the role of the function g(t), which is crucial for establishing the system's nonlinearity.

PREREQUISITES
  • Understanding of continuous-time processing systems
  • Familiarity with impulse response functions
  • Knowledge of linear stability conditions in systems theory
  • Basic mathematical proof techniques in system analysis
NEXT STEPS
  • Study the implications of nonlinear systems in control theory
  • Learn about the role of impulse responses in system characterization
  • Explore the mathematical foundations of linearity and nonlinearity in systems
  • Investigate the function g(t) and its impact on system behavior
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Students and professionals in electrical engineering, control systems, and applied mathematics who are analyzing system behaviors and stability conditions.

Jimmy Johnson
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Homework Statement


Consider the continuous-time processing system in figure 1, which has two inputs and one output. The linear sub-system H is characterised by the impulse response h(t) = e −2t , where t denotes time.

Block diagram is the product of x1(t) and x2(t) going through a block step of h(t) (exp-2t)

Give a mathematical proof that this is a nonlinear system.

Question attached in picture.

Homework Equations


α1y1(t) + α2y2(t) = H {α1x1(t) + α2x2(t)} , condition for linear stability

where x1(t) and x2(t) are two input signals and y1(t) and y2(t) are the corresponding output signals for system H

The Attempt at a Solution



Would my equations become

y1(t) = x1(t)e(-2t)

y2(t) = x2(t)e(-2t)

then calculating one way

y(t) = α1x1(t)e(-2t) + α2x2(t)e(-2t)

then the other

y(t) = e(-2t)[α1x1(t) + α2x2(t)] = α1x1(t)e(-2t) + α2x2(t)e(-2t)

But that would suggest linearity... Is there something I'm missing?
 

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Jimmy Johnson said:

Homework Statement


Consider the continuous-time processing system in figure 1, which has two inputs and one output. The linear sub-system H is characterised by the impulse response h(t) = e −2t , where t denotes time.

Block diagram is the product of x1(t) and x2(t) going through a block step of h(t) (exp-2t)

Give a mathematical proof that this is a nonlinear system.

Question attached in picture.

Homework Equations


α1y1(t) + α2y2(t) = H {α1x1(t) + α2x2(t)} , condition for linear stability

where x1(t) and x2(t) are two input signals and y1(t) and y2(t) are the corresponding output signals for system H

The Attempt at a Solution



Would my equations become

y1(t) = x1(t)e(-2t)

y2(t) = x2(t)e(-2t)

then calculating one way

y(t) = α1x1(t)e(-2t) + α2x2(t)e(-2t)

then the other

y(t) = e(-2t)[α1x1(t) + α2x2(t)] = α1x1(t)e(-2t) + α2x2(t)e(-2t)

But that would suggest linearity... Is there something I'm missing?

You seem to be missing totally that the input to H is g(t) and inventing two outputs y when there is only one.

Seem. Thisnis not my field but it sure seems.
 
Jimmy Johnson said:

Homework Statement


Consider the continuous-time processing system in figure 1, which has two inputs and one output. The linear sub-system H is characterised by the impulse response h(t) = e −2t , where t denotes time.

Block diagram is the product of x1(t) and x2(t) going through a block step of h(t) (exp-2t)

Give a mathematical proof that this is a nonlinear system.

Question attached in picture.

Homework Equations


α1y1(t) + α2y2(t) = H {α1x1(t) + α2x2(t)} , condition for linear stability

where x1(t) and x2(t) are two input signals and y1(t) and y2(t) are the corresponding output signals for system H

The Attempt at a Solution



Would my equations become

y1(t) = x1(t)e(-2t)

y2(t) = x2(t)e(-2t)

then calculating one way

y(t) = α1x1(t)e(-2t) + α2x2(t)e(-2t)

then the other

y(t) = e(-2t)[α1x1(t) + α2x2(t)] = α1x1(t)e(-2t) + α2x2(t)e(-2t)

But that would suggest linearity... Is there something I'm missing?

Yes, you are missing the effects of "g".
 

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