- #1
Eutrophicati
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I'm sorry, I just realized I put this in the wrong subsection. While I figure out how to fix that, please have a look anyway.
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Given x [itex]\inℝ[/itex]
And s =[itex]\frac{4(x^{2}) + 3}{2x-1}[/itex]
Prove that [itex]s^{2}[/itex] -4s - 12 ≥ 0
The discriminant Δ, (in order for which to be real must be ≥ 0)
b^2 - 4ac ≥ 0
Doing the algebra isn't the problem, I'm having trouble understanding the question itself. For this sort of proof, don't I need to work with
s =[itex]\frac{4(x^{2}) + 3}{2x-1}[/itex]
instead of the statement to be proven, which is [itex]s^{2}[/itex] -4s - 12 ≥ 0?
In which case, how do I apply the b^2 - 4ac rule with the linear equation part in the denominator?
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Homework Statement
Given x [itex]\inℝ[/itex]
And s =[itex]\frac{4(x^{2}) + 3}{2x-1}[/itex]
Prove that [itex]s^{2}[/itex] -4s - 12 ≥ 0
Homework Equations
The discriminant Δ, (in order for which to be real must be ≥ 0)
b^2 - 4ac ≥ 0
The Attempt at a Solution
Doing the algebra isn't the problem, I'm having trouble understanding the question itself. For this sort of proof, don't I need to work with
s =[itex]\frac{4(x^{2}) + 3}{2x-1}[/itex]
instead of the statement to be proven, which is [itex]s^{2}[/itex] -4s - 12 ≥ 0?
In which case, how do I apply the b^2 - 4ac rule with the linear equation part in the denominator?
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