Two forces P and Q are applied at the end of a screw eye in order to remove the post.
The two equations that were found are
The Attempt at a Solution
I combined the 2 equations by first solving (1) in terms of Q=2*P*sin(θ)
then plugged into equation (2) (2*P*sin(θ))*cos(30)+P*cos(θ)-800=0
then got f(θ)=sin(θ)*(√3)*P+P*cos(θ)-800=0
wanted f(θ)=0 as final equation
f'(θ)=P*(2*cos(30)*cos(θ)-sin(θ) (i do not think this is correct though)
Then I have to write a newton raphson for θ for a given P and solve for θ.
use P=400 to 800 with ΔP=25.
compute θ for each P
once θ is found for each P use equation (1) to find Q
Now plot P and Q for each θ.
I am very new to Matlab. (only introduced to it 2 weeks ago) and i am not to sure how to start. This is what i came up with but it is very confusing to me.
x0=400; n=16; eps=0.001; fun=@(tha) 2*p*sin(tha)*cos(30)+p*cos(tha)-800=0; fund=@(x) p*(2*cos(30)*cos(x)-sin(x); nr=(x0,n,eps,fun,fund)
function nr(x0, n, eps, f, fd)
fprintf ('%4d %8.4f %8.4f %8.4f\n',i,func, dfunc, x)
if abs(x-x0) < eps , break, end
**i know there needs to be an M-File for this set up but i am not sure how to do that either.
Thanks in advance for the help