Matrix Simplification: A = HG(FHG)^{-1}FG | Step-by-Step Solution

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SUMMARY

The discussion focuses on the simplification of the matrix equation A = HG(FHG)^{-1}FG. The key steps involve recognizing that (FHG)^{-1} can be expressed as F^{-1}H^{-1}G^{-1}, leading to the simplification of A to G after applying properties of the identity matrix. Participants clarify that the identity matrix I does not appear in the final expression because multiplying by I does not change the matrix. The final result of the simplification is A = G.

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Homework Statement



Simplify

A = HG(FHG)[tex]^{-1}[/tex]FG

Homework Equations



None

The Attempt at a Solution



Well (FHG)^-1 is really just F^-1 H^-1 G^-1
Therefore A = HGG[tex]^{-1}[/tex]H[tex]^{-1}[/tex]F[tex]^{-1}[/tex]FG
GG^-1 = I
FF-1 = I

Therefore A = HIH[tex]^{-1}[/tex](IG)

The book now simplifies to HH[tex]^{-1}[/tex]G

I understand all the steps and the ending step, but I don't get how they got rid of the two I's

I X I = I (Identity Matrix), so where did it disappear to?

The final answer is: A = G

Thanks
 
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Urgh, silly me, solved.

Identity matrix multiplied by another matrix just returns that matrix I forgot.

Silly problem. Sorry.
 
JFonseka said:
Well (FHG)^-1 is really just F^-1 H^-1 G^-1

Not really. (FHG)^-1 = (G^-1)*(H^-1)*(F^-1).
 

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