Matter density right after the decoupling

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SUMMARY

The discussion centers on the matter density of the universe immediately following the decoupling of photons from matter, which resulted in the cosmic microwave background radiation. It is established that the matter density at redshift z=1100 is approximately 2.1 x 109 hydrogen atoms per cubic meter, significantly lower than the density of air at Earth's surface, which is 2.5 x 1025 molecules per cubic meter. This low density allowed for the free-streaming of photons, meaning they could travel without significant interaction with matter. The implications of this density on the observable universe's radius are also discussed, emphasizing the importance of understanding the early universe's conditions.

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  • Understanding of cosmic microwave background radiation
  • Familiarity with redshift calculations in cosmology
  • Knowledge of plasma physics and its interaction with light
  • Basic principles of the observable universe and its radius calculations
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Astronomers, cosmologists, and physics students interested in the early universe, cosmic microwave background radiation, and the dynamics of light in low-density environments.

janeczek
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Once photons decoupled from matter, they traveled freely through the universe without interacting with matter and constitute what is observed today as cosmic microwave background radiation (in that sense, the cosmic background radiation is infrared and some red black-body radiation emitted when the universe was at a temperature of some 3000 K, redshifted by a factor of 1100 from the visible spectrum to the microwave spectrum).
https://en.wikipedia.org/wiki/Recombination_(cosmology)

Was a matter density right after the decoupling low enough to consider the vacuum as the actual vacuum, and not the medium through which the light propagates with the speed lower than ##({\epsilon_0\mu_0})^{-1/2}##? I'm asking this in context of the calculation of the observable universe radius, where the time integral of the inverse of the scale factor is multiplied by the constant speed of light ##c##.
 
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janeczek said:
Was a matter density right after the decoupling low enough to consider the vacuum as the actual vacuum
The Wikipedia page you linked to gives a formula for the number density of hydrogen as a function of the redshift ##z##. From that you can calculate what the matter density would be. What do you get?
 
Is ##Q_H## the energy of hydrogen ionization?
 
janeczek said:
Is ##Q_H## the energy of hydrogen ionization?
Yes. But you don't need to know that to do the calculation I described in post #2.
 
Right... So the formula for the total density of hydrogen is ##(1+z)^3\cdot 1.6\,m^{-3}##.

So for ##z=0## it's 1.6 hydrogen atoms per cubic meter... Right after the decoupling or today? More like today I guess.

So for ##z=1100## it's ##1101^3 \cdot 1.6## hydrogen atoms per cubic meter... That gives ~##2.1\cdot 10^9## atoms per cubic meter.
 
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janeczek said:
https://en.wikipedia.org/wiki/Recombination_(cosmology)

Was a matter density right after the decoupling low enough to consider the vacuum as the actual vacuum, and not the medium through which the light propagates with the speed lower than ##({\epsilon_0\mu_0})^{-1/2}##? I'm asking this in context of the calculation of the observable universe radius, where the time integral of the inverse of the scale factor is multiplied by the constant speed of light ##c##.
I consider the radius of the observable universe to be, by definition, the greatest distance that anything could reach during the age of the universe propagating at speed ##c##, that is, without taking into account that, on average, the speed of light in a given non-empty medium may be less than ##c##.
 
janeczek said:
Right... So the formula for the total density of hydrogen is ##(1+z)^3\cdot 1.6\,m^{-3}##.
Yes.

janeczek said:
So for ##z=0## it's 1.6 hydrogen atoms per cubic meter... Right after the decoupling or today? More like today I guess.
Yes, ##z = 0## means now.

janeczek said:
So for ##z=1100## it's ##1101^3 \cdot 1.6## hydrogen atoms per cubic meter... That gives ~##2.1\cdot 10^9## atoms per cubic meter.
Yes. How does that compare to, say, the number density of particles per cubic meter in air at the surface of the Earth today?
 
Number density of air is ##2.5\cdot 10^{25}## molecules per cubic meter... It's larger by 16 orders of magnitude.

Now that makes me wonder how could light be "trapped" in such "low" density plasma before the recombination...
 
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Jaime Rudas said:
I consider the radius of the observable universe to be, by definition, the greatest distance that anything could reach during the age of the universe propagating at speed ##c##, that is, without taking into account that, on average, the speed of light in a given non-empty medium may be less than ##c##.
On the other hand, the margin of error in calculating the age of the universe is on the order of hundreds of millions of years, so what happened in the first 380,000 years is irrelevant for calculating the observable universe radius.
 
  • #10
janeczek said:
Number density of air is ##2.5\cdot 10^{25}## molecules per cubic meter... It's larger by 16 orders of magnitude.
Yes.

janeczek said:
Now that makes me wonder how could light be "trapped" in such "low" density plasma before the recombination...
Because plasma doesn't work like air. Even at such extremely low density, it interacts strongly with light.
 
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  • #11
PeterDonis said:
Because plasma doesn't work like air. Even at such extremely low density, it interacts strongly with light.
Compare to the density of the Sun's photosphere. The number density of hydrogen there is about ##10^{24}## per cubic meter. But of course the Sun is rather small in comparison to the Universe and we must remember what we mean by the light in the early Universe not being free-streaming - it means that it will interact within the age of the Universe, i.e., essentially comparing the interaction rate to the Hubble rate at the time. The photosphere is also not fully ionized.
 
  • #12
janeczek said:
Once photons decoupled from matter, they traveled freely through the universe without interacting with matter
That doesn't make sense to me. Why would photons not interact with matter, when encountering it? We are not talking about neutrinos here, after all.
 
  • #13
phinds said:
That doesn't make sense to me. Why would photons not interact with matter, when encountering it? We are not talking about neutrinos here, after all.
Free-streaming means that the (average) density of matter is so small that the mean-free path exceeds the size of the Universe. The Universe is pretty low density after all.
 
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  • #14
Orodruin said:
Free-streaming means that the (average) density of matter is so small that the mean-free path exceeds the size of the Universe. The Universe is pretty low density after all.
Thanks for that clarification.
 

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